Question

我正在使用这段代码尝试获取我在网站上打印的所有最新推文，但它返回了一个关于未经过身份验证的错误。我在Dev部分创建了一个应用程序并获取了我的消费者和OAuth密钥，并将它们添加到代码中的正确位置。

    <?php
        function buildBaseString($baseURI, $method, $params) {
            $r = array();
        ksort($params);
        foreach($params as $key=>$value){
            $r[] = "$key=" . rawurlencode($value);
        }
        return $method."&" . rawurlencode($baseURI) . '&' . rawurlencode(implode('&', $r));
        }

        function buildAuthorizationHeader($oauth) {
        $r = 'Authorization: OAuth ';
        $values = array();
        foreach($oauth as $key=>$value)
            $values[] = "$key=\"" . rawurlencode($value) . "\"";
        $r .= implode(', ', $values);
        return $r;
        }

        $url = "https://api.twitter.com/1.1/statuses/user_timeline.json?screen_name=jameskrawczyk";
        $oauth_access_token = "SECURITY";
        $oauth_access_token_secret = "SECURITY";
        $consumer_key = "SECURITY";
        $consumer_secret = "SECURITY";

        $oauth = array( 'oauth_consumer_key' => $consumer_key,
                    'oauth_nonce' => time(),
                    'oauth_signature_method' => 'HMAC-SHA1',
                    'oauth_token' => $oauth_access_token,
                    'oauth_timestamp' => time(),
                    'oauth_version' => '1.0');



        $base_info = buildBaseString($url, 'GET', $oauth);
        $composite_key = rawurlencode($consumer_secret) . '&' .     rawurlencode($oauth_access_token_secret);
        $oauth_signature = base64_encode(hash_hmac('sha1', $base_info, $composite_key, true));
        $oauth['oauth_signature'] = $oauth_signature;



        $header = array(buildAuthorizationHeader($oauth), 'Expect:');
        $options = array( CURLOPT_HTTPHEADER => $header,
                      //CURLOPT_POSTFIELDS => $postfields,
                      CURLOPT_HEADER => false,
                      CURLOPT_URL => $url,
                      CURLOPT_RETURNTRANSFER => true,
                      CURLOPT_SSL_VERIFYPEER => false);



        $feed = curl_init();
        curl_setopt_array($feed, $options);
        $json = curl_exec($feed);
        curl_close($feed);
        $twitter_data = json_decode($json, true);
        foreach ($twitter_data as $elem)
        {
          print_r($elem);
          echo '<br>';
        }

页面

返回错误

Array ( [0] => Array ( [message] => Could not authenticate you [code] => 32 ) )

Answer 1

答案似乎是那条线

$url = "https://api.twitter.com/1.1/statuses/user_timeline.json?screen_name=jameskrawczyk";

最后不应该有?screen_name=jameskrawczyk。

Answer 2

您必须使用库从Twitter获取数据 “themattharris”是一个优秀而着名的图书馆，可从here
下载

Twitter API PHP获取最新推文不进行身份验证

2 个答案: