我有两个模型,Benefit和SchemeName
福利 -
[Key]
public int BenefitID { get; set; }
public string BenefitName { get; set; }
public string BenefitDescription { get; set; }
public virtual ICollection<SchemeName> SchemeNames { get; set; }
SchemeName
[Key]
public int SchemeNameID { get; set; }
public string Name { get; set; }
public virtual ICollection<Benefit> Benefits { get; set; }
这在数据库的Benefits,SchemeNames和一个名为SchemeNameBenefits的连接表中创建了三个表。
我正在尝试填充仅包含与某个Benefit关联的SchemeNames的droplownlist,但我不知道如何执行此操作,我可以在代码中引用连接表吗?
我从以下开始(返回所有SchemeNames)
private void PopulatePensionSchemeName(object selectedPensionSchemeName = null)
{
var schemeNameQuery = from d in db.SchemeNames
orderby d.SchemeNameID
select d;
ViewBag.PensionSchemeNameID = new SelectList(schemeNameQuery, "SchemeNameID", "Name", selectedPensionSchemeName);
}
但我不确定如何添加此条款。有什么指针吗?
答案 0 :(得分:2)
您需要SchemeNames所需的Benefit对象的键。您可能正在寻找的查询是: -
var benefitId = // However you get your benefit Id
var schemaNameQuery = from b in db.Benefits
from s in b.SchemeNames
where b.BenefitId == benefitId
select s;
或者在扩展方法语法中: -
var schemaNameQuery = db.Benefits.Where(b.BenefitId == benefitId)
.SelectMany(b => b.SchemeNames);
产生以下SQL: -
SELECT ...
FROM [dbo].[SchemeNameBenefits] AS [Extent1]
INNER JOIN [dbo].[SchemeNames] AS [Extent2]
ON [Extent1].[SchemeName_Id] = [Extent2].[SchemeNameId]
WHERE [Extent1].[Benefit_Id] = @p__linq__0
或者您可以使用: -
var benefitId = // However you get your benefit Id
var schemeNameQuery = from d in db.SchemeNames
where d.Benefits.Any(x => x.Id == benefitId)
orderby d.SchemeNameId
select d;
这会生成以下SQL: -
SELECT ...
FROM ( SELECT ... FROM [dbo].[SchemeNames] AS [Extent1]
WHERE EXISTS (SELECT 1 AS [C1]
FROM [dbo].[SchemeNameBenefits] AS [Extent2]
WHERE ([Extent1].[SchemeNameId] = [Extent2].[SchemeName_Id])
AND ([Extent2].[Benefit_Id] = @p__linq__0)))
AS ...
ORDER BY [Project2].[Id] ASC
请注意,在这两种情况下,生成的SQL都会引用您的联结表,即使它不是您的EF模型的一部分。
如果您已经拥有了Benefit对象,当然,您可以通过以下方式更简单地获取其SchemeNames: -
var schemeNameQuery = benefit.SchemeNames;
答案 1 :(得分:1)
我会通过使用连接表来完成此操作。连接表是您的连接表。它将包含两个外键,SchemeNameID&amp; BenefitID。
查看本网站了解更多有关接线表的信息:
http://megocode3.wordpress.com/2008/01/04/understanding-a-sql-junction-table/
它帮助了我很多。
答案 2 :(得分:1)
[免责声明]有条件存在或添加SchemeNameBenefits模型,以下内容应该有效。
因此,似乎SchemeNameBenefits表是多对多映射,在这种情况下使用收益ID来获取方案ID的集合
var schemeIds = db.SchemeNamesBenefits.Where(map => map.BenefitID == id)
.Select(map => map.SchemeNameID).ToArray();
然后撤回这些方案ID的所有方案名称信息
var result = db.SchemeNames.Where(scheme => schemeIds.Contains(scheme.SchemeNameID))
.OrderBy(scheme => scheme.SchemeNameId)
.Select(scheme => scheme.Name).ToArray();
或在一个查询中
var result = db.SchemeNamesBenefits.Where(map => map.BenefitID == id)
.SelectMany(map => db.SchemeNames
.Where(scheme => map.SchemeNameID == scheme.SchemeNameID)
.OrderBy(scheme => scheme.SchemeNameId)
.Select(scheme => scheme.Name)
.AsEnumerable())
.ToArray()