Question

我有这个PHP代码，我收到此错误：解析错误：语法错误，意外'}'，期待';'在第120行的[文件位置]

while（$ array etc等）的行是第120行。

if($numrows != 0)
{
    do
    {
        //echo "<a href='approve.php?ref=" . $array['id'] . "'>Your '" . $array['keywords'] . "' article has been written and needs to be reviewed.</a>";
        //echo "<br />";
    } while($array = mysql_fetch_array($result)) //While there are still rows in the SELECT query.
}

想法？我必须失明。谢谢！

Answer 1

} while($array = mysql_fetch_array($result))

应该是

} while($array = mysql_fetch_array($result));

do-while

顺便说一句，代码片段似乎应该使用while循环，除非您是第一次故意使用旧值$array。

Answer 2

在你的声明结束时a;缺少:) while($array = mysql_fetch_array($result));

Answer 3

在;声明

的末尾错过了分号while

while($array = mysql_fetch_array($result)); //<---- add semicolon here

Answer 4

                if($numrows != 0)
                {
                    do
                    {
                        //echo "<a href='approve.php?ref=" . $array['id'] . "'>Your '" . $array['keywords'] . "' article has been written and needs to be reviewed.</a>";
                        //echo "<br />";
                    } while($array = mysql_fetch_array($result)); //While there are still rows in the SELECT query.
                }

在条件

之后忘记了;

PHP语法错误。我瞎了吗？

4 个答案: