import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;
import java.io.DataOutputStream;
import java.io.InputStream;
public class TestingPost {
public static void main(String args[]) {
URL url;
HttpURLConnection connection = null;
String targetURL=".....";//here is my local server url
String urlParameters="{\"clubhash\":\"100457d41b9-ab22-4825-9393-ac7f6e8ff961\",\"username\":\"anonymous\",\"message\":\"simply awesome\",\"timestamp\":\"2012/11/05 13:00:00\"}";
try {
//Create connection
url = new URL(targetURL);
connection = (HttpURLConnection)url.openConnection();
connection.setRequestMethod("POST");
connection.setRequestProperty("Content-Type",
"application/x-www-form-urlencoded");
connection.setRequestProperty("Content-Length", "" +
Integer.toString(urlParameters.getBytes().length));
connection.setRequestProperty("Content-Language", "en-US");
connection.setUseCaches (false);
connection.setDoInput(true);
connection.setDoOutput(true);
//Send request
DataOutputStream wr = new DataOutputStream (
connection.getOutputStream ());
wr.writeBytes (urlParameters);
wr.flush ();
wr.close ();
//Get Response
InputStream is = connection.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
String line;
StringBuffer response = new StringBuffer();
while((line = rd.readLine()) != null) {
response.append(line);
response.append('\r');
}
rd.close();
System.out.println("message="+response.toString());
} catch (Exception e) {
e.printStackTrace();
} finally {
if(connection != null) {
connection.disconnect();
}
}
}
}
我正在尝试使用HTTP POST方法发送JSON对象。以上是代码,但我正在
java.io.IOException: Server returned HTTP response code: 415 for URL: ....
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
at TestingPost.main(TestingPost.java:38)"
我的代码出了什么问题?
答案 0 :(得分:39)
您获得的HTTP响应代码是
415 Unsupported Media Type
这意味着服务器无法处理您发送给它的格式。您的HTTP请求设置了此标头:
Content-Type: application/x-www-form-urlencoded
这是提交表单时浏览器发送的内容类型。如果要发送JSON,请使用此标头:
Content-Type: application/json
答案 1 :(得分:0)
我正确传递
=INDEX(Sheet2!$B$1:$B$3,AGGREGATE(15,6,ROW(Sheet2!$A$1:$A$3)/(ISNUMBER(SEARCH(Sheet2!$A$1:$A$3,A1))),1))
但是我的服务器仍在拒绝请求,因为我也在传递
Content-Type: application/json
我的情况不允许这样做。