Question

您好我想找到一个带有文本字符串“CAT1”的xml节点并显示但我似乎无法正确使用它。有人可以告诉我什么是错的。

--- ---的catalog.xml

<?xml version="1.0" encoding="ISO-8859-1"?>
<Catalog>
    <Category>
        <Name>CAT1</Name>
        <Location>
            <Room> Alpha </Room>
        </Location>  
    </Category>
    <Category>
        <Name>CAT2</Name>
        <Location>
            <Room> Bravo </Room>
        </Location>  
    </Category>
    <Category>
        <Name>CAT3</Name>
        <Location>
            <Room> Charlie </Room>
        </Location>  
    </Category>
    <Category>
        <Name>CAT4</Name>
        <Location>
            <Room> Delta </Room>
        </Location>  
    </Category>
</Catalog>

--- --- arr0.php

<?php
$catalog = simplexml_load_file("catalog.xml");
$category = $catalog->Category;
$name = $category->Name;
$location = $category->Location;
$room = $location->Room;

for ($i = 0; $i <= 22; $i++)
{
$display = $catalog->xpath("//Category/Name[contains(text("CAT1"),'".$category[$i]->$name."']/parent::");
{
echo $display;
echo $room;
}
}
?>

结果是显示节点[类别] [名称] = CAT1，[位置] [房间]下列出的所有详细信息，但我显示错误

解析错误：语法错误，第11行/home/a3440614/public_html/arr0.php中的意外T_STRING

任何有助于纠正和简化它的帮助。

由于

PHP：如何显示XML xpath中定义的子节点？

0 个答案: