Question

 class AddItemOption
{
    //Fields that contain class data
    string input = Console.ReadLine(); 
   //Methods that define class functionality
    public string myFunction(string Value)
    {
        switch (input)
        {
            case "Umbrella":
               Console.WriteLine("Umbrella is selected");
               break;
            case "Rain Coat":
               Console.WriteLine("Raincoat is selected");
               break;
            case "Boots":
                Console.WriteLine("Boots is selected"); 
                break;
            case "Hood":
                Console.WriteLine("Hood is selected");
                break;
            default:
                Console.WriteLine("Input not reconized, please choose another item");
                break;


        }

    }

我收到错误“并非所有代码路径都返回值”。它来自myFunction（字符串值）。我不知道如何返回这个，或者在参数中添加什么以使其工作。我也需要它下面的东西吗？我是新上课的。请告诉我，如果我这样做是错误的，或者这是switch语句应该去的地方！

   public AddItemOption(string input) 

        {


        }

来自Shyju我改为：

class AddItemOptionOne
{
    //Fields that contain class data
    string input = Console.ReadLine(); 
   //Methods that define class functionality
    public string myFunction(string Value)
    {
        switch (input)
        {
            case "Key Chain":
               return "Key Chain is selected";
               break;
            case "Leather Armor":
               return "Leather Armor is selected";
               break;
            case "Boots":
                return "Boots is selected"; 
                break;
            case "Sword":
                return "Sword is selected";
                break;
            default:
                return "Input not reconized, please choose another item";
                break;


        }
    }

然而，它不承认休息。 “检测到无法访问的代码”

Answer 1

您的方法的返回类型为string。这意味着您的方法应始终返回某些字符串。但是你没有返回一个字符串。而是使用WriteLine方法将其写入控制台。

所以改变

Console.WriteLine("Umbrella is selected");

到

return "Umbrella is selected";

或

您可以将方法的返回类型更改为void。

public void myFunction(string Value) { //your current fancy stuff here Console.WriteLine("My method dont have a return type"); }

编辑：根据问题编辑AS。

return语句将从您的方法中取出控件。这意味着下一行（break）将不会被执行。所以删除break语句。

case "Key Chain": return "Key Chain is selected";

Answer 2

嗯......你没有从你的函数返回任何东西，所以把它改成

public void myFunction(string Value)

Answer 3

试试这个：

class AddItemOptionOne
{
    //Methods that define class functionality
    public string myFunction(string input)
    {
        string result = string.Empty;

        switch (input)
        {
            case "Key Chain":
                result = "Key Chain is selected";
                break;
            case "Leather Armor":
                result = "Leather Armor is selected";
                break;
            case "Boots":
                result = "Boots is selected";
                break;
            case "Sword":
                result = "Sword is selected";
                break;
            default:
                result = "Input not reconized, please choose another item";
                break;
        }

        return result;
    }
}

带字符串开关的类

3 个答案: