我正在尝试在qml生成的窗口中绘制图形。因为我需要使用QML进行GUI(客户端要求)。我设法在QML中获取图形窗口,但它没有绘制任何内容。我不知道我的代码是否正确,请建议,指出我正确的方向。
main.py:
#! /usr/bin/python
import os
import sys
from PySide import QtGui
from PySide import QtCore
from PySide import QtDeclarative
import numpy as np
import pyqtgraph as pg
class Graph (QtDeclarative.QDeclarativeItem):
def __init__(self, parent = None):
QtDeclarative.QDeclarativeItem.__init__(self, parent)
#----------- self.setFlag(QtGui.QGraphicsItem.ItemHasNoContents, False )
self.dataPlot = np.cos(np.linspace(0, 5 *np.pi , 1000))
self.graph = pg.PlotItem()
self.graph.plot( self.dataPlot, pen=(0,255,0))
self.graph.showGrid(x=True, y=True)
self.view = pg.GraphicsView()
self.view.setCentralItem(self.graph)
#-------------------------------------- self.setCentralWidget(self.view)
mProxy = QtGui.QGraphicsProxyWidget(self)
mProxy.setWidget(self.view)
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
QtDeclarative.qmlRegisterType(Graph, 'myPyQtGraph', 1, 0, 'PyQtGraph')
view = QtDeclarative.QDeclarativeView()
view.setSource(QtCore.QUrl('main.qml'))
view.setResizeMode(QtDeclarative.QDeclarativeView.SizeRootObjectToView)
rootObject = view.rootObject()
view.connect(view.engine() , QtCore.SIGNAL('quit()') ,app.instance( ) , QtCore.SLOT('quit()') )
view.show()
sys.exit(app.exec_())
main.qml:
import QtQuick 1.1
import myPyQtGraph 1.0
Rectangle {
id : page
width: 900
height: 400
color: "#343434"
PyQtGraph {
id: angleGraphID
anchors{
top: parent.top
left: parent.left
topMargin: 50
leftMargin: 50
}
width: 800
height: 300
//color: "#f5deb3"
}
Text {
id: text_Heading
anchors{
top: parent.top
left: parent.left
topMargin: 20
leftMargin: 50
}
text: qsTr("PyqtGraph QML Test")
font.pixelSize: 12
}
}
这就是我现在所得到的:
答案 0 :(得分:2)
我最好的猜测是问题与此错误有关: http://srinikom.github.com/pyside-bz-archive/932.html
然而,它似乎只是QML上下文中的问题,因为PySide在QML之外工作正常。 你可以通过在pyqtgraph / graphicsItems / GraphicsObject.py中注释掉'itemChange'方法来解决这个问题。