Question

我的一系列方法是这样的：

onUpdateAcrossDown ( findAcrossAndDownWords( across_index, down_index ) )

我想重用findAcrossAndDownWords，所以我希望它能够返回我可以传递给其他方法的两个对象。

findAcrossAndDownWords: function(across_index, down_index) {
  across_word = across_index[0] // <-- not real, just representing that it becomes an object here.
  down_word = down_index[0]
  return [across_word, down_word] // <-- This is where my problem is. Not sure how to return a double param for my parent function.
}

问题是，我使用的return没有正确传递across_word, down_word。

onUpdateAcrossDown: function(across_word, down_word) {
 // How do I get across_word and down_word here properly?

Answer 1

如果要将数组中的值用作函数的参数，则必须使用.apply()

调用该函数

var results = findAcrossAndDownWords( across_index, down_index );
onUpdateAcrossDown.apply(whatever, results);

.apply()方法有两个参数：被调用函数中用于this的值，以及一个包含要传递的参数的数组。

Answer 2

您可以将第二个函数作为参数传递，而不是嵌套调用：

findAcrossAndDownWords(across_index, down_index, onUpdateAcrossDown);

function findAcrossAndDownWords(object1, object2, callNext)
{
    //do stuff
    return callNext(object1, object2);
}

或者，将第二个函数的函数定义更改为：

function UpdateAcrossDown(anArray)
{
    var obj1 = anArray[0], obj2 = anArray[1];
}

或，如果你总是打算调用相同的功能：

function findAcrossAndDownWords(object1, object2, callNext)
{
    //do stuff
    return UpdateAcrossDown(object1, object2);//loses call context
    return UpdateAcrossDown.apply(this,arguments);//preserve called context
    //or even
    return UpdateAcrossDown.apply(this,[object1,object2]);//preserve called context
}

如何通过jQuery中的两个函数正确传递两个对象

2 个答案: