Question

如何使用格式通过* printf（）函数系列从输出字符串中删除字符？这是可能的？

来自宏这个宏：

  char *s =
    g_strdup_printf(
    "insert into foo(name,serie,"
#define X(a, b) #a ","
    LIST ") "
#undef X
#define X(a, b) "%d,"
    "values('%s'," LIST "%d" ")",
#undef X
#define X(a, b) bol->a,
    boletim->aname, serie, LIST
#undef X
            );

我输出的内容如下：

  char *s =
    g_strdup_printf(
    "insert into foo(name,serie,"

    "red" "," "blue" "," "yellow" "," "purple" "," ") "


    "values('%s'," "%d," "%d," "%d," "%d," "%d" ")",


    boletim->aname, serie, boletim->red, boletim->blue, boletim->yellow, boletim->purple,

      );

puts(s)来电显示以下内容：

insert into foo(name,serie,red,blue,yellow,purple,) values('Ari tol',-1,-1,-1,-1,0)

但是我遇到了问题，,在第一个)之前导致SQL查询失效。我正在寻找一些方法将其从字符串中删除。也许通过某种格式可以在printf()函数族中使用或重新定义宏。我不知道。这只是尝试不编写首先搜索)索引的例程，然后再按索引调用字符串替换函数。

Answer 1

您无法在预处理器级别删除内容。但是，在这种情况下，您可以定义X以在每个项目之前放置逗号，并在“serie”和“'％s'”之后删除逗号。

如何使用格式从* printf（）函数系列中删除输出字符串中的字符？

1 个答案: