表
id string
------------
1 aaa
2 bbb
3 ccc
4 ddd
查询
(SELECT string FROM table WHERE id > 1 ORDER BY id ASC LIMIT 1) /* num_row = 1 */
UNION
(SELECT string FROM table WHERE id < 1 ORDER BY id DESC LIMIT 1) /* null */
UNION
(SELECT string FROM table WHERE id > 4 ORDER BY id ASC LIMIT 1) /* null */
UNION
(SELECT string FROM table WHERE id < 4 ORDER BY id DESC LIMIT 1) /* num_row = 2 */
上面的查询将返回2 rows
,因为没有id = 5且id = 0。
如何判断从这两行获取哪些查询?
即来自num_row = 1
的{{1}}和来自1st SELECT
的{{1}}
答案 0 :(得分:2)
你可以尝试
(SELECT 1, string FROM table WHERE id > 1 ORDER BY id ASC LIMIT 1)
UNION
(SELECT 2, string FROM table WHERE id < 1 ORDER BY id DESC LIMIT 1)
UNION
(SELECT 3, string FROM table WHERE id > 4 ORDER BY id ASC LIMIT 1)
UNION
(SELECT 4, string FROM table WHERE id < 4 ORDER BY id DESC LIMIT 1)
答案 1 :(得分:0)
您可以使用常用别名添加额外的常量列:
(SELECT string, 'query_1' as query_num FROM table WHERE id > 1 ORDER BY id ASC LIMIT 1)
UNION
(SELECT string, 'query_2' as query_num FROM table WHERE id < 1 ORDER BY id DESC LIMIT 1)
UNION
(SELECT string, 'query_3' as query_num FROM table WHERE id > 4 ORDER BY id ASC LIMIT 1)
UNION
(SELECT string, 'query_4' as query_num FROM table WHERE id < 4 ORDER BY id DESC LIMIT 1)
答案 2 :(得分:0)
使用第二列来指示数据来自何处
(SELECT string, '1st query' as from_where FROM table WHERE ...)
UNION
(SELECT string, '2nd query' as from_whereFROM table WHERE ...)
答案 3 :(得分:0)
你可以尝试(虽然不优雅):
(SELECT'1',string FROM table WHERE id&gt; 1 ORDER BY id ASC LIMIT 1)/ * num_row = 1 / 联盟 (SELECT'2',string FROM table WHERE id&lt; 1 ORDER BY id DESC LIMIT 1)/ null / 联盟 (SELECT'3',string FROM table WHERE id&gt; 4 ORDER BY id ASC LIMIT 1)/ null / 联盟 (SELECT'4',string FROM table WHERE id&lt; 4 ORDER BY id DESC LIMIT 1)/ num_row = 2