Question

我知道标题有点令人困惑，但这是一个例子：

字符串：SELECT * FROM tbl_clients ORDER BY updatedOn LIMIT 0,50

我想要的是在 FROM之后取出所有并将其放入新的字符串中。

所以我的结果字符串看起来像是：tbl_clients ORDER BY updatedOn LIMIT 0,50

有没有办法做他的？

Answer 1

好吧，你可以这样使用explode：

$string="SELECT * FROM tbl_clients ORDER BY updatedOn LIMIT 0,50";
$split=explode("FROM", $string, 2); 
//Restricts the split to 2 elements, i.e., everything after first occurrence goes in the second element

$result=$split[1];

Answer 2

您可以尝试类似

的内容

$mystring = "SELECT * FROM tbl_clients ORDER BY updatedOn LIMIT 0,50";
$spliter = "FROM ";
$splitstring = explode($spliter, $mystring);

$result = $splitstring[1];

Answer 3

有很多方法可以做到这一点（stripos-substr，explode）等，但这里有 preg_split（）方式：

$sql = 
    "SELECT * FROM tbl_clients ORDER BY updatedOn " .
    "WHERE `from`='something' LIMIT 0,50";
$r = preg_split( "/FROM /i", $sql );
print_r( $r );

给你$ r [1]玩：

Array
(
    [0] => SELECT * 
    [1] => tbl_clients ORDER BY updatedOn WHERE `from`='something' LIMIT 0,50
)

在某些情况下，preg_split可能非常方便，比如解析整个语句：

$r = preg_split( "/(SELECT)|(FROM)|(ORDER BY)|(WHERE)|(LIMIT)/i", $sql );

在一个声明中给你一个更简洁的细分：

Array
(
    [0] => 
    [1] =>  * 
    [2] =>  tbl_clients 
    [3] =>  updatedOn 
    [4] =>  field='something' 
    [5] =>  0,50
)

Answer 4

split FROM上的字符串为您提供数组，然后访问数组的第1个元素。

$query_array = preg_split("/FROM /i", "SELECT a,b,d FROM tableA WHERE b=2", 1);
$table_and_clause = $query_array[1];  // "tableA WHERE b=2"...

Answer 5

对于无法阅读strpos()和substr()

的相应手册页的用户

$string = 'SELECT * FROM tbl_clients ORDER BY updatedOn LIMIT 0,50';
$pos = strpos($string, ' FROM ');
$substring = substr($string, $pos + strlen(' FROM '));

给定字符串后的PHP拆分字符串

5 个答案: