我在code.cpp中声明了以下枚举 并且我使用的switch语句取决于枚举的设置。
enum State { HighMoral, PoorMoral, EndGame };
State CurrentState = HighMoral;
switch (CurrentState)
{
case HighMoral: random = rand()%3+1;
switch (random)
{
case 1: CurrentState = g_Solider.KillCommander(&CurrentState, random = rand()%2+1);
break;
case 2: CurrentState = g_Solider.KillSeniorCommander(&CurrentState,random = rand()%2+1);
break;
case 3: CurrentState = g_Solider.LessHalfStrength(&CurrentState);
break;
};
break;
case PoorMoral: CurrentState = g_Solider.JoinSeniorCommander();
break;
};
我想将此枚举传递给类中的函数,然后让它返回HighMoral
,PoorMoral
或EndGame
并更改switch语句的当前状态。
然而,当涉及到传递并返回时,我相当无能为力。 我环顾四周,没有找到如何做到这一点的运气。
我有3个档案。 code.cpp(包含void main()
和enum
),solider.h(包含solider类不知道状态枚举存在(怎么做?)),solider.cpp(包含所有的solider代码)但需要采取当前状态并返回一个新状态)
以下是我正在尝试做的一个例子。
Solider.h
#include <time.h>
#include <iostream>
using namespace std;
extern enum State;
class Solider
{
private:
public:
void KillSeniorCommander(State& currentState, int random); // Kill the Senior Commander or random event
void JoinSeniorCommander(State& currentState); // Have the Commander join the group
void DefunctGroup(State& currentState); // Disband the group
};
Solider.cpp
void Solider::KillSeniorCommander(State& currentState, int random)
{
if (SeniorCommander==1) // If The SeniorCommander is Active
{
cout << "The Senior Commander has died!\n";
SeniorCommander--; // Kill the SeniorCommander
Groupsize--; // Reduce the Groupsize
Strength = Strength - (5*2.5); // Remove SeniorCommanders impact on Strength
SquadMoral = SquadMoral - (5*2.5);// Remove SeniorCommanders impact on SquadMoral
CurrentState = PoorMoral;
}
else // Otherwise do something random
{
switch (random)
{
case 1: cout << "Your group survives a ambush!\n";
break;
case 2: random = rand()%5+1; // Give random a new value
if (random>1)
{
cout << random << " group members have died!\n"; // Kill x Aamount of members
}
else
{
cout << "A group member has died!\n"; // Kill a member
}
Groupsize = Groupsize - random; // Remove the members from the group
Strength = Strength - (random*2.5); // Remove there effect Strength
SquadMoral = SquadMoral - (random*2.5); // Remove there effect on GroupMoral
break;
}
CurrentState = CurrentState;
}
} // KillSeniorCommander(int random)
void Solider::JoinSeniorCommander(State& currentState)
{
if (SeniorCommander==2 && Commander == 0) // Check to see if the Commander is dead and a
{ // SeniorCommander is not in service
cout << "The Senior Commander has joined!\n";
SeniorCommander--; // Change their status to active
Groupsize++; // Add them to the group
Strength = Strength - (5*2.5); // Add their impact to Strength
SquadMoral = SquadMoral - (5*2.5); // Add their impact to GroupMoral
CurrentState = HighMoral;
}
else // He isn't available to join
{
cout << "You fail to recruit new command!\n";
CurrentState = CurrentState;
}
} // JoinSeniorCommander()
void Solider::DefunctGroup(State& currentState)
{
cout << "Your group has been disbanded as it is not fit for duty.";
CurrentState = EndGame;
} // DefunctGroup()
code.cpp
答案 0 :(得分:0)
枚举可以在接口中被视为整数。您可以使用以下两种方法:通过引用传递并使函数有意更改,或按值传递并按值返回下一个State
:
// one or the other
void nextState( State& currentState );
State nextState( State currentState );
答案 1 :(得分:0)
与C ++中的其他内容一样,您需要查看要使用的内容的声明。在您的情况下,这意味着必须将State
的定义移动到头文件中,然后将该文件包含在main.cpp和soldier.h中。然后,您将能够在State
成员函数的声明中使用Soldier
类型。
答案 2 :(得分:0)
在标题中定义枚举,并在两个文件中包含该标题。
例如:
#ifndef SOLDIERSTATE_H
#define SOLDIERSTATE_H
enum SoldierState
{
HighMorale,
PoorMorale,
EndGame
};
#endif
答案 3 :(得分:-1)
class Game
{
public:
enum State { HighMoral, PoorMoral, EndGame };
aMethod(State::PoorMoral);
};
Game::aMethod(State aState)
{
return State::HighMoral;
}