Question

我从php程序请求java soap web服务。我的代码就像关注

<?php
 $options = array('features' => 
    SOAP_USE_XSI_ARRAY_TYPE + SOAP_SINGLE_ELEMENT_ARRAYS);
try{
     $sClient = new SoapClient('http://192.168.1.101:8080/person/Person.wsdl');
    //  $sClient = new SoapClient('http://192.168.1.11:8080/DNAHMS/webservice/onlineBooking/Hotel.wsdl',$options);
        //$params = array('Id'=> '1');
        echo "<pre>";
        print_r($sClient->__getFunctions());
        echo "</pre>";

        $parms  = array("Id"=>1);
        $response = $sClient->__call('getPerson',$parms);
        echo "<pre>";
        print_r($response);
        echo "</pre>";





    } catch(SoapFault $e){
        echo "<pre>";
            var_dump($e);
        echo "<pre>";
    }
    ?>

这里我是Person.wsdl，当我直接调用浏览器它没有错误，并且这是有效的xml文件。当我运行这个时，我会得到如下的肥皂故障：

cvc-complex-type.4：属性'Id'必须出现在元素'ns1：GetPersonRequest'上任何帮助都会感激不尽

Answer 1

这个链接可以帮到你：

http://php.net/manual/en/soapclient.soapcall.php

How to make a PHP SOAP call using the SoapClient class

肥皂错误：请求时出现XML验证错误：cvc-complex-type.4：属性'Id'必须出现在元素上

1 个答案: