这是我的Facebook应用程序来源
<?php
require 'facebook.php';
require 'config.php';
if (isset($_GET['code'])){
header("Location: " . $canvasPage);
exit;
}
$fb = new Facebook(array(
'appId' => 'xxx',
'secret' => 'xxxx',
'cookie' => true,
'fileUpload' => true,
));
$me = null;
$user = $fb->getUser();
if($user) {
try {
$me = $fb->api('/me');
} catch(FacebookApiException $e) {
error_log($e);
}
}
//edit the permissions needed
$permsneeded='publish_stream,user_photos';
if ($me){}
else {
$loginUrl = $fb->getLoginUrl(array(
'scope' => $permsneeded,
));
echo "
<script type='text/javascript'>
window.top.location.href = '$loginUrl';
</script>
";
exit;
}
if(isset($_GET['signed_request'])) {
$fb_args="signed_request=". $_REQUEST
['signed_request']; }
$signed_request = $_REQUEST["signed_request"];
list($encoded_sig, $payload) = explode(".", $signed_request, 2);
$data = json_decode(base64_decode(strtr($payload, "-_", "+/")), true);
if (empty($data["user_id"]))
{
echo("");
}
$access_token = $data["oauth_token"];
try {
$my = $fb->api('/me');
}catch(FacebookApiException $e) {
error_log($e);
}
$nam = $my['name'];
$images = array(
0 => 'celeb/1.jpg',
1 => 'celeb/1.jpg',
3 => 'celeb/1.jpg',
4 => 'celeb/1.jpg',
5 => 'celeb/1.jpg',
6 => 'celeb/1.jpg',
);
$image = $images[ rand(0,(count($images)-1)) ];
Some other php code
?>
<html xmlns="http://www.w3.org/1999/xhtml" xmlns:og="http://opengraphprotocol.org/schema/" >
My Code .
</html>
我遇到了2个问题。
答案 0 :(得分:0)
请尝试这样做,请避免使用空白的陈述。
if(!($me))
{
echo '<script> top.location.href="'.$facebook->getLoginUrl(array(
'req_perms' => $permsneeded,
'next' =>'https://apps.facebook.com/246435698815637/',
)). '";
</script>';
exit();
}
第二个是正确的,它应该可以工作,但我不明白你对imagecreatefromjpeg
的看法,因为你没有提供任何关于它的信息。在你使用该功能的地方使用代码。