Question

好的，所以我在编程任务上遇到了很多麻烦。我们将从文本文件中读取信息，并使用我们创建的某些方法对其进行格式化。我能够很好地从文本文件的第一行读取信息，但后来我收到错误。我的代码如下：

String name1 = scan.nextLine();
    String name2 = scan.nextLine();
    scan.close();
    int length = name1.length();
    int count = 0;
    int a = 0;
    int b = 1;
    while(end != true)
    {

        String check = name1.substring(a,b);
        a++;
        b++;
        count++;
        char z = check.charAt(0);
        if(z == '0' || z == '1' || z == '2' || z == '3' || z == '4' || z == '5' || z == '6' || z == '7' || z == '8' || z == '9')
        {
            end = true;

        }
        if(count == length)
        {
            end = true;

        }
    }
    String number1 = name1.substring(count,length);
    int number01 = Integer.parseInt(number1);
    name1=name1.substring(0, count-1);
    int d = name1.indexOf(" ");
    int length1 = name1.length();
    String name1first = name1.substring(0,d);
    name1first = name1first.trim();
    String name1last = name1.substring(d,length1);
    name1last = name1last.trim();

    System.out.println(name1first);
    System.out.println(name1last);
    System.out.println(number01);


    length = name2.length();
   int  countt = 0;
int  aa = 0;
int  bb = 1;
    while(end != true)
    {

        String check = name2.substring(aa,bb);
        aa++;
        bb++;
        countt++;
        char z = check.charAt(0);
        if(z == '0' || z == '1' || z == '2' || z == '3' || z == '4' || z == '5' || z == '6' || z == '7' || z == '8' || z == '9')
        {
            end = true;

        }
        if(countt == length)
        {
            end = true;

        }
    }
    String number2 = name2.substring(countt,length);
    int number02 = Integer.parseInt(number2);
    name2=name2.substring(0, countt-1);
    d = name2.indexOf(" ");
    int length2 = name2.length();
    String name2first = name2.substring(0,d);
    name2first = name2first.trim();
    String name2last = name2.substring(d,length2);
    name2last = name2last.trim();

    System.out.println(name2first);
    System.out.println(name2last);
    System.out.println(number02);

我收到此错误：

Exception in thread "main" java.lang.NumberFormatException: For input string: "Jennifer Sutter 52114"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at Salary.main(Salary.java:101)

Answer 1

这显然是为什么你得到那个例外：

您正在尝试将“Jennifer Sutter 52114”转换为整数。

解决方法是在尝试呼叫try{}catch()时首先使用Integer.parseInt()阻止。

我认为你正在尝试获取最后一点字符串并将其转换为整数：并且由于你使用的是Scanner，你可以nextInt()就这样：

new Scanner(theStringWhichMightHaveANumber).nextInt();

如何在java中将多个字符串解析为int

1 个答案: