我有一个mysql dynamic-sql语句,我想用pdo运行它,我收到以下错误信息:
警告:PDOStatement :: fetchAll()[pdostatement.fetchall]: SQLSTATE [HY000]:C:\ xampp \ htdocs \ tags \ cobasql.php中的常规错误 第29行
这是我的PHP代码:
<?php
$uname = 'root'; //nama username database
$pwd = ''; //Password database
$dbname = 'eav_latihan'; //nama Database
/* Initialisasi database */
$db = new PDO('mysql:host=localhost;dbname='.$dbname, $uname, $pwd);
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING);
$query = "SET @sql = NULL; ".
" SELECT GROUP_CONCAT(DISTINCT CONCAT('MAX(IF(a.Name = ''', ".
" a.Name, ''', ca.value, NULL)) AS ', a.Name )) INTO @sql ".
" FROM cust_attribute ca ".
" INNER JOIN attribute a ON ca.idAttribute = a.idAttribute ".
" INNER JOIN customer c ON c.idCustomer = ca.idCustomer ".
" WHERE a.publish = 'Y'; ".
" SET @sql = CONCAT('SELECT c.idCustomer, c.namaCustomer, ' ".
" ' c.email, c.noTelp, ', @sql, ' FROM cust_attribute ca', ".
" ' INNER JOIN attribute a ON ca.idAttribute = a.idAttribute', ".
" ' INNER JOIN customer c ON c.idCustomer = ca.idCustomer', ".
" ' GROUP BY c.idCustomer'); ".
" SELECT @sql; ".
" prepare stmt FROM @sql; ".
" execute stmt;";
$result_array = array();
$queryku = $db->query($query);
$result_array = $queryku->fetchAll(PDO::FETCH_OBJ);
echo $result_array;
?>
这里有人可以帮我或者给我一个建议吗?
答案 0 :(得分:-1)
好像你连接不了!
这一行
$db = new PDO('mysql:host=localhost;dbname='.$dbname, $uname, $pwd);
尝试删除$ db name var并输入正确的值,使您的行看起来像
$db = new PDO('mysql:host=localhost;dbname=dbname', $uname, $pwd);