NetBeans中的错误(通过SQlite连接)使用单选按钮

时间:2012-11-04 06:14:11

标签: sqlite netbeans

下面给出的程序不是执行rs1(结果集查询)而是直接进入catch块。我无法识别错误。请帮助。

private void EnterActionPerformed(java.awt.event.ActionEvent evt)
{                                      
   Calendar cal=new GregorianCalendar();
   int minute =cal.get(Calendar.MINUTE);
   int hours=cal.get(Calendar.HOUR);
    String time1=minute+":"+hours;
    String s=Login_page.id+"";
    String sql="UPDATE emp_info SET intime=? where empid=?";

    try
    {
        switch (time) 
        {
            case "intime":
                {

                    //"Update emp_info set intime='"+time1+"' where empid=?";
                    System.out.println(time+Login_page.id); 
                    PreparedStatement pst1=conn.prepareStatement(sql);
                    pst.setString(1,time1);
                    pst.setString(2,s);
                    System.out.println(time+Login_page.id); 
                    ResultSet rs1=pst.executeQuery();
                    if(rs.next())
                    {
                        JOptionPane.showMessageDialog(null,"In time registered");

                    }

                    break;
                }
            case "outtime":
                {
                    //String sql="Insert into emp_info (outtime) values (?) where empid='"+Login_page.id+"'";

                   //pst=conn.prepareStatement(sql);
                    //pst.setString(1,time1);
                    //pst.setString(2,Login_page.user);
                    //rs=pst.executeQuery();
                    PreparedStatement pst2=conn.prepareStatement(sql);
                    pst.setString(1,time1);
                    pst.setString(2,s);
                    System.out.println(time+Login_page.id); 
                    ResultSet rs2=pst.executeQuery();
                    if(rs.next())
                    {
                        JOptionPane.showMessageDialog(null,"In time registered");

                    }
                    break;
                }
        }
}                                     
        catch(Exception e)
    { 
        JOptionPane.showMessageDialog(null,"ERROR","ERROR",JOptionPane.WARNING_MESSAGE);
    }


}

0 个答案:

没有答案