Question

这是较大项目的一小部分。我只需要获取未读电子邮件并解析其标题。如何修改以下脚本以仅获取未读电子邮件？

conn = imaplib.IMAP4_SSL(imap_server)
conn.login(imap_user, imap_password)

status, messages = conn.select('INBOX')    

if status != "OK":
    print "Incorrect mail box"
    exit()

print messages

Answer 1

这样的事情可以解决问题。

conn = imaplib.IMAP4_SSL(imap_server)

try:
    (retcode, capabilities) = conn.login(imap_user, imap_password)
except:
    print sys.exc_info()[1]
    sys.exit(1)

conn.select(readonly=1) # Select inbox or default namespace
(retcode, messages) = conn.search(None, '(UNSEEN)')
if retcode == 'OK':
    for num in messages[0].split(' '):
        print 'Processing :', message
        typ, data = conn.fetch(num,'(RFC822)')
        msg = email.message_from_string(data[0][1])
        typ, data = conn.store(num,'-FLAGS','\\Seen')
        if ret == 'OK':
            print data,'\n',30*'-'
            print msg

conn.close()

此处还有一个重复的问题 - Find new messages added to an imap mailbox since I last checked with python imaplib2?

两个有用的功能，可以检索您检测到的新邮件的正文和附件（参考：How to fetch an email body using imaplib in python?） -

def getMsgs(servername="myimapserverfqdn"):
  usernm = getpass.getuser()
  passwd = getpass.getpass()
  subject = 'Your SSL Certificate'
  conn = imaplib.IMAP4_SSL(servername)
  conn.login(usernm,passwd)
  conn.select('Inbox')
  typ, data = conn.search(None,'(UNSEEN SUBJECT "%s")' % subject)
  for num in data[0].split():
    typ, data = conn.fetch(num,'(RFC822)')
    msg = email.message_from_string(data[0][1])
    typ, data = conn.store(num,'-FLAGS','\\Seen')
    yield msg

def getAttachment(msg,check):
  for part in msg.walk():
    if part.get_content_type() == 'application/octet-stream':
      if check(part.get_filename()):
        return part.get_payload(decode=1)

Answer 2

上面的答案实际上不再起作用或者从来没有做过但我修改了它所以它只返回看不见的消息，它曾经给出：错误无法解析fetch命令或类似的东西这里是一个工作代码：

mail = imaplib.IMAP4_SSL('imap.gmail.com')
(retcode, capabilities) = mail.login('email','pass')
mail.list()
mail.select('inbox')

n=0
(retcode, messages) = mail.search(None, '(UNSEEN)')
if retcode == 'OK':

   for num in messages[0].split() :
      print 'Processing '
      n=n+1
      typ, data = mail.fetch(num,'(RFC822)')
      for response_part in data:
         if isinstance(response_part, tuple):
             original = email.message_from_string(response_part[1])

             print original['From']
             print original['Subject']
             typ, data = mail.store(num,'+FLAGS','\\Seen')

print n

我认为错误来自messages[0].split(' ')，但上面的代码应该可以正常工作。

另请注意+FLAGS而非-FLAGS将邮件标记为已读。

Answer 3

original = email.message_from_string(response_part[1])

需要更改为：

original = email.message_from_bytes(response_part[1])

Answer 4

我已设法使用Gmail工作：

public static Expression<Func<MyModel, String>> GetSomeStatus()
{
    return myModel => myModel.IsTrue ? "That's true" : "That's false";
}

Answer 5

您可以使用imap_tools软件包： https://pypi.org/project/imap-tools/

from imap_tools import MailBox, Q
with MailBox('imap.mail.com').login('test@mail.com', 'password') as mailbox:
    # get unseen emails from INBOX folder
    for msg in mailbox.fetch(Q(seen=False)):
        print(msg.headers)

只获取新的电子邮件imaplib和python

5 个答案: