Question

我是Linux新手，不懂编程。但通过阅读一些我能理解的事情，我可以提出质疑。

我正在做类似下面的事情，

在文件中找到几个单词并在另一个文件中相应地执行操作。

find in log.txt
if "not found" 1 > notify.txt
if "reset by peer" 2 > notify.txt
if "Permission denied" 3 > notify.txt
if "Fetching" 0 > notify.txt
exit

像

if [it found] "not found" [text in the log.txt then it will write] 1 > notify.txt
if [it found] "reset by peer" [text in the log.txt then it will write] 2 > notify.txt
if [it found] "Permission denied" [text in the log.txt then it will write] 3 > notify.txt
if [it found] "Fetching" [text in the log.txt then it will write] 0 > notify.txt

请帮我写剧本。

我想写一下notify.txt 0或1或2或3。现在脚本将决定写什么。脚本将通过读取log.txt文件来决定。

由于

Answer 1

你的问题有些含糊不清，但我相信这就是你要找的东西：

#!/bin/bash

# Put the source file / output file in variables
# so they are easier to change
src_file=log.txt
outfile=notify.txt

# Look for the patterns in the source file with "grep":
not_found=$(grep "not found" $src_file)
reset_by_peer=$(grep "reset by peer" $src_file)
perm_denied=$(grep "Permission denied" $src_file)
fetching=$(grep "Fetching" $src_file)

# If the output file already exists, remove it
if [[ -f $outfile ]]; then
    rm -f $outfile
fi

# Create a blank output file
touch $outfile

# If any of the patterns are found, print a number accordingly:
if [[ -n $not_found ]]; then
    echo "1" >> $outfile
fi 

if [[ -n $reset_by_peer ]]; then
    echo "2" >> $outfile
fi 

if [[ -n $perm_denied ]]; then
    echo "3" >> $outfile
fi 

if [[ -n $fetching ]]; then
    echo "0" >> $outfile
fi

由于您使用多个if块而不是一个if-else if-...-else块来构建问题，我假设源文件中可能存在多个模式，如果是这样，您希望在数据库中显示多个数字输出文件。（虽然即使src文件中只存在其中一个模式，这也有效）

grep一个文件并找到多个单词并相应地采取行动

1 个答案: