Question

我是django的新手。我有这个模型，在tblperson中，只保存类型和状态的forgein键。如何加入所有表格以显示其值而不是其forgein键？例如。

TblPerson.objects.raw('SELECT * FROM "Tblperson" INNER JOIN "Tblstatus" ON ("TblPerson"."Status" = "Tblstatus"."ID")'):

感谢。

class TblPerson(models.Model):
    ID = models.AutoField(primary_key=True, db_column=u'ID') 
    Type = models.IntegerField(null=True, db_column=u'Type', blank=True)
    Status = models.IntegerField(null=True, db_column=u'Status', blank=True)
    class Meta:
        db_table = u'tblPerson'

class Tblstatus(models.Model):
    ID = models.AutoField(primary_key=True, db_column=u'statStatusID')
    Status = models.CharField(max_length=25, db_column=u'statStatus', blank=True)
    class Meta:
        db_table = u'tblStatus'

class Tbltype(models.Model):
    ID = models.AutoField(primary_key=True, db_column=u'typTypeID')
    Type = models.CharField(max_length=25, db_column=u'typType', blank=True)
    class Meta:
        db_table = u'tblType'

Answer 1

Django的力量在ORM，这意味着如果有的话，你应该写很少的SQL。

   class Person(models.Model):
        #don't use this because id is generated automatically
        #ID = models.AutoField(primary_key=True, db_column=u'ID')            

        type = models.ForeignKey(Type)
        status = models.ForeignKey(Status)


    #Type,Status analogous

    #filter like this
    selected = Person.objects.filter(type=SomeType)
    for p in selected:
        print p.id,p.type,p.status

Answer 2

我建议你重新编写模型。所以，你的TblPerson与Tblstatus有多对一的关系

class TblPerson(models.Model):
    ID = models.AutoField(primary_key=True, db_column=u'ID') 
    Type = models.IntegerField(null=True, db_column=u'Type', blank=True)
    Status = models.ForeignKey(Tblstatus, null=True, db_column=u'Status', blank=True)
    class Meta:
        db_table = u'tblPerson'

class Tblstatus(models.Model):
    ID = models.AutoField(primary_key=True, db_column=u'statStatusID')
    Status = models.CharField(max_length=25, db_column=u'statStatus', blank=True)
    class Meta:
        db_table = u'tblStatus'

使用此功能，您可以查询Tblstatus存在的TblPerson对象

TblPerson.objects.filter(Status__isnull=False)

django加入查询

2 个答案: