Question

我正在尝试在我的献血者应用程序中创建搜索/过滤选项。可以通过性别，姓名，血型或通过选择所有三种来搜索捐赠者。这是我的代码

function search_donar($_POST) {

        $by_name = $_POST['by_name'];
        $by_sex = $_POST['by_sex'];
        $by_group = $_POST['by_group'];
        $by_level = $_POST['by_level'];

        $search_query = "SELECT * FROM donar WHERE";
        if($by_name !="") {
          $search_query .= " name='$by_name'";
        }
        if($by_sex !="") {
          $search_query .= " sex='$by_sex'";
        }
        if($by_group !="") {
          $search_query .= " blood_group='$by_group'";
        }
        if($by_level !="") {
          $search_query .= " e_level='$by_level'";
        }
        $search_query;
        $result = mysql_query($search_query);

        return $result;
    }

这是html

if(isset($_POST['submit'])) {

    $retrived_result = $donar->search_donar($_POST);

}

   <form action="" method="post">
    <table width="100%" border="0" style="border:none;">
      <tr>
        <td><label>Name:&nbsp;</label><input type="text" name="by_name" /></td>
        <td><label>Sex:&nbsp;</label><input type="text" name="by_sex" /></td>
        <td><label>Blood Group:&nbsp;</label><input type="text" name="by_group" /></td>
        <td><label>Level:&nbsp;</label><input type="text" name="by_level" /></td>
        <td><input class="button" type="submit" name="submit" value="Search" /></td>
      </tr>
    </table>
    </form>

单次过滤非常好。但要过滤所有我使用的AND，但它给了我错误。有人可以帮忙吗？

提前致谢

Answer 1

与所有其他帖子一样，您需要使用AND附加所有条件。到目前为止，这是最干净的答案。记住要使用mysqli OOP方式而不是旧的mysql来真正逃避你的字符串。只是一个建议。

以下是典型查询的示例。

正确的方法：

SELECT * FROM donar WHERE name='dxenaretionx' AND sex='M';

你这样做的方式

SELECT * FROM donar WHERE name='dxenaretionx' sex='M';

代码：

function search_donar($_POST) {
    $by_name = $_POST['by_name'];
    $by_sex = $_POST['by_sex'];
    $by_group = $_POST['by_group'];
    $by_level = $_POST['by_level'];

    //Do real escaping here

    $query = "SELECT * FROM donar";
    $conditions = array();

    if(! empty($by_name)) {
      $conditions[] = "name='$by_name'";
    }
    if(! empty($by_sex)) {
      $conditions[] = "sex='$by_sex'";
    }
    if(! empty($by_group)) {
      $conditions[] = "blood_group='$by_group'";
    }
    if(! empty($by_level)) {
      $conditions[] = "e_level='$by_level'";
    }

    $sql = $query;
    if (count($conditions) > 0) {
      $sql .= " WHERE " . implode(' AND ', $conditions);
    }

    $result = mysql_query($sql);

    return $result;
}

Answer 2

以下代码段：

$search_query = "SELECT * FROM donar WHERE";
if($by_name !="") {
  $search_query .= " name='$by_name'";
}
if($by_sex !="") {
  $search_query .= " sex='$by_sex'";
}

生成类似

的查询

SELECT * FROM donar WHERE name='nowak' sex='m'

，这是无效的，因为子句之间没有逻辑运算符。你需要添加一个'AND'。为了简化代码，您可以以“true和a和b ......”的形式生成条件：

$search_query = "SELECT * FROM donar WHERE true";
if($by_name !="") {
  $search_query .= " AND name='$by_name'";
}
if($by_sex !="") {
  $search_query .= " AND sex='$by_sex'";
}
...

Answer 3

在你的代码中有条件的查询有问题。这里你的查询就像 select * from donar where by_name = "A" by_group = "N"没有And/Or来确定条件。请尝试下面给出的代码。

$search_query = "SELECT * FROM donar";
$query_cond = "";

if($by_name !="") {
      $query_cond .= " name='$by_name'";
}
if($by_sex !="") {

      if(!empty($query_cond)){
          $query_cond .= " AND ";
       }

      $query_cond .= " sex='$by_sex'";
}

if($by_group !="") {

      if(!empty($query_cond)){
          $query_cond .= " AND ";
       }

      $query_cond .= " blood_group='$by_group'";
}

if($by_level !="") {

      if(!empty($query_cond)){
          $query_cond .= " OR ";
       }

      $query_cond .= " e_level='$by_level'";
 }

 if(!empty($query_cond)){
      $query_cond = " Where ".$query_cond;
      $search_query.$query_cond;
 }

这里的代码首先我们将$query_cond变量设为空并根据代码生成条件。并根据这个管理AND运营商。最后，如果我们发现$query_cond不为空，请将其添加到$select_query。

我希望它会对你有所帮助。

感谢

Answer 4

试试这样：

function search_donar($_POST) {

        $by_name = $_POST['by_name'];
        $by_sex = $_POST['by_sex'];
        $by_group = $_POST['by_group'];
        $by_level = $_POST['by_level'];

        $isfirst=0;
        $search_query = "SELECT * FROM donar WHERE";
        if($by_name !="") {

          $search_query .= " name='$by_name'";
          $isfirst=1;
        }
        if($by_sex !="") {
            if($isfirst!=0)
            $search_query .= " AND ";
          $search_query .= " sex='$by_sex'";
          $isfirst=1;
        }
        if($by_group !="") {
            if($isfirst!=0)
            $search_query .= " AND ";
          $search_query .= " blood_group='$by_group'";
          $isfirst=1;
        }
        if($by_level !="") {
            if($isfirst!=0)
            $search_query .= " AND ";
          $search_query .= " e_level='$by_level'";
          $isfirst=1;
        }
        $result = mysql_query($search_query);

        return $result;
    }

Answer 5

在这里你不使用验证，建议不要使用Field是EMPTY还是NOT。试试下面的代码，希望它能运作

function search_donar($_POST) {

    $by_name = $_POST['by_name'];
    $by_sex = $_POST['by_sex'];
    $by_group = $_POST['by_group'];
    $by_level = $_POST['by_level'];

    $search_query = "SELECT * FROM donar WHERE name LIKE '%$by_name%' AND sex LIKE '%$by_sex%' AND blood_group LIKE '%$by_group%' AND  e_level LIKE '%$by_level%' ";

    $result = mysql_query($search_query);

    return $result;
}

Answer 6

function search_donar($_POST) {

    $by_name = $_POST['by_name'];
    $by_sex = $_POST['by_sex'];
    $by_group = $_POST['by_group'];
    $by_level = $_POST['by_level'];

    $search_query = "SELECT * FROM donar WHERE";

    $and = '';
    if(count($_POST) > 1) {
        $and ='AND';
    }
    if($_POST[0]) {
        $and ='';
    }

    if($by_name !="") {
        $search_query .= $and." name='$by_name'";
    }
    if($by_sex !="") {
        $search_query .= $and." sex='$by_sex'";
    }
    if($by_group !="") {
        $search_query .= $and." blood_group='$by_group'";
    }
    if($by_level !="") {
        $search_query .= $and." e_level='$by_level'";
    }

    if(count($_POST) == 0) {
        $search_query .= " 1 ";
    }

    $search_query;
    $result = mysql_query($search_query);

    return $result;
}

Answer 7

我会这样。

function search_donar($_POST) {

    $by_name = $_POST['by_name'];
    $by_sex = $_POST['by_sex'];
    $by_group = $_POST['by_group'];
    $by_level = $_POST['by_level'];

    $search_query = "SELECT * FROM donar WHERE 1 = 1";
    if($by_name !="") {
      $search_query .= " AND name='$by_name'";
    }
    if($by_sex !="") {
      $search_query .= " AND sex='$by_sex'";
    }
    if($by_group !="") {
      $search_query .= " AND blood_group='$by_group'";
    }
    if($by_level !="") {
      $search_query .= " AND e_level='$by_level'";
    }
    $result = mysql_query($search_query);
    return $result;
}

使用PHP / MySQL搜索过滤

7 个答案: