Question

我正在尝试运行一个基本上如下所示的查询：

INSERT INTO lessons_skills_xref (lessons_id, skills_id)
SELECT id FROM lessons, (SELECT id FROM skills WHERE title = "title 1")
/* PSEUDO CODE - Where the ids for both lesson and skill don't already exist */

不确定如何完成最后一部分。有什么想法吗？

Answer 1

假设lessons_skills_xref在（lessons_id，skills_id）上有唯一键，一种简单的方法就是使用INSERT IGNORE

INSERT IGNORE INTO lessons_skills_xref (lessons_id, skills_id)
SELECT id, (SELECT id FROM skills WHERE title = "title 1") FROM lessons

如果记录尚不存在，INSERT IGNORE语法将插入记录，如果记录已经存在，则忽略它。

Answer 2

INSERT INTO lessons_skills_xref (lessons_id, skills_id)

SELECT lessons.id, skills.id FROM lessons
inner join skills on <join criteria here>

where not exists (select 1 from lessons_skill_xref x where
                  x.lessons_id = lessons.id and x.skills_id = skills.id)

and skills.title = "title 1"

Answer 3

您是否尝试在每个lesson.id和“title 1”技能的skills.id之间生成笛卡尔联接？我不确定你的SELECT子句是否有效。这可能是：

    INSERT INTO lessons_skills_xref (lessons_id, skills_id)
    (SELECT l.id, s.id FROM lessons l, skills s 
        WHERE s.title = "title 1"
        AND NOT EXISTS 
            (SELECT * FROM lessons_skills_xref 
                WHERE lessons_id=l.id 
                AND skills_id=s.id)
    );

请注意，这是未经测试的。

如果记录尚不存在，MySQL INSERT SELECT FROM多个表

3 个答案: