Question

我想尝试一种方法，每次有新的cookie设置或每次用户登录和退出时，我都可以从文件夹中的大约100个图像中选择显示5个图像。我已经尝试过使用javascript来显示基于星期几的不同图像，但是我真正想要的是一种方法，一次显示5个图像，附加的链接会在每次用户登录和注销时更改？有人能指出我的写作方向，我是php的新手，所以即使最小的代码示例也会有所帮助，谢谢。

继承我的javascript代码，显示基于当天的图片，我不知道这是否有用？

<script type="text/javascript" language="JavaScript">
var now = new Date ();
var day = now.getDay();
//the week begins on SUNDAY
if(day == 0) document.write("<p><a href='YOUR-LINK-HERE'><img src='../PTB1/data/adverts/ad0.png' alt='sunday' width='180' height='180' border='0'></a></p><p><a href='YOUR-LINK-HERE'><img src='../PTB1/data/adverts/ad0.png' alt='sunday' width='180' height='180' border='0'></a></p>");
if(day == 1) document.write("<a href='YOUR-LINK-HERE'><img src='../PTB1/data/adverts/ad1.png' alt='monday' width='180' height='180' border='0'></a>");
if(day == 2) document.write("<a href='YOUR-LINK-HERE'><img src='../PTB1/data/adverts/ad2.png' alt='tuesday' width='180' height='180' border='0'></a>");
if(day == 3) document.write("<a href='YOUR-LINK-HERE'><img src='../PTB1/data/adverts/ad3.png' alt='wednesday' width='180' height='180' border='0'></a>");
if(day == 4) document.write("<a href='YOUR-LINK-HERE'><img src='../PTB1/data/adverts/ad4.png' alt='thursday' width='180' height='180' border='0'></a>");
if(day == 5) document.write("<a href='YOUR-LINK-HERE'><img src='../PTB1/data/adverts/ad5.png' alt='friday' width='180' height='180' border='0'></a>");
if(day == 6) document.write("<a href='YOUR-LINK-HERE'><img src='../PTB1/data/adverts/ad6.png' alt='saturday' width='180' height='180' border='0'></a>");
</script>

Answer 1

如果你想从一组已知图像中显示5个随机图像，这是最好的方法

$imagepool=array('path1.jpg','path2.jpg', ..... ,'path100.jpg');
for($i=0;$i<5;$i++){
  $randid=floor(rand(0,100));
  echo '<a href="#"><img src="'.$imagepool[$randid].'"></a>';
}

或者，如果您对所有这些图像都有这样的命名方案并且它们是有序的，那么您不必定义图像列表：

for($i=0;$i<5;$i++){
  $randid=floor(rand(0,100));
  echo '<a href="#"><img src="/path/to/image_'.$randid.'.jpg"></a>';
}

Answer 2

<script type="text/javascript" language="JavaScript">
var now = new Date ();
var day = now.getDay();
var images = new Array(7);
var weekday=new Array(7);
images[0] = '../PTB1/data/adverts/ad0.png';
images[1] = '../PTB1/data/adverts/ad1.png';
images[2] = '../PTB1/data/adverts/ad2.png';
images[3] = '../PTB1/data/adverts/ad3.png';
images[4] = '../PTB1/data/adverts/ad4.png';
images[5] = '../PTB1/data/adverts/ad5.png';
images[6] = '../PTB1/data/adverts/ad6.png';
weekday[0]="Sunday";
weekday[1]="Monday";
weekday[2]="Tuesday";
weekday[3]="Wednesday";
weekday[4]="Thursday";
weekday[5]="Friday";
weekday[6]="Saturday";
document.write("<p><a href='YOUR-LINK-HERE'><img src='"+images[day]+"' alt='"+weekday[day]+"' width='180' height='180' border='0'></a></p>");
</script>

Answer 3

我认为您也可以使用date()和strtotime()来完成PHP中的五个链接/图像：

<?php
$today = strtotime("today");
$today = date('w',$today);
if ($today==0) echo '<a...><img.../></a>';
if ($today==1) echo '<a...><img.../></a>';
//etc...

如果你想随机，我相信你可以在登录时在PHP中设置一个$_SESSION变量，它将五个图像作为变量。如果他们退出并再次登录，变量将会改变，你将有五个新的图像/链接（无论你在寻找什么）。

这是你能做的。创建一个变量的php文件，以及一个用于处理登录的php文件：

<?php
    //variables page
    $your_link_array = array("GOOGLE" => "http://www.google.com","Stackoverflow" => "http://www.stackoverflow.com", "Youtube" => "http://www.youtube.com"); //three as an example, but you should make a lot if you want to pull five each time.
    ?>

    <?php 
    //log in page

    if($login=='success'){ //check username/password etc.
      session_start(); //log in successful
      $_SESSION['links'] = array_rand($your_link_array, 5); //pull 5 random variables from your array of links
    }
    ?>

    <?php
    //any other page that has session_start() at the beginning:
    session_start()
    foreach($_SESSION['links'] as $k => $v){ // show the five random links
      echo '<a href="'.$k.'" />'.$v.'</a>';
    } 
    ?>

其他资源：array_rand，foreach

显示每个cookie或每个会话的随机图像和链接？

3 个答案: