我目前在MySQL数据库中有5个表。它们中的一些共享外键并且彼此相互依赖。我正在向他们的专业展示相应的课程。我有两个专业:计算机工程师和信息系统。它们的值存储在名为major的表中。他们各自的身份证是1和2.我在所有课程的总时数上遇到了困难。如何添加每个课程时间并在页面底部显示专业的总小时数?
<?
try {
$pdo = new PDO ("mysql:host=$hostname;dbname=$dbname","$username","$pw");
} catch (PDOException $e) {
echo "Failed to get DB handle: " . $e->getMessage() . "\n";
exit;
}
$query = $pdo->prepare("SELECT course.name, course.code, course.description, course.hours,
CASE semester.semester
WHEN 0 THEN 'Spring'
WHEN 1 THEN 'Fall'
WHEN 2 THEN 'All-year'
END semester, semester.year
FROM course
LEFT JOIN major_course_xref ON course.id = major_course_xref.course_id
LEFT JOIN major ON major.id = major_course_xref.major_id
LEFT JOIN course_semester_xref ON course.id = course_semester_xref.course_id
LEFT JOIN semester ON course_semester_xref.semester_id = semester.id
Where major.id = '1'
");
$query->execute();
if ($query->execute()){
while ($row = $query->fetch(PDO::FETCH_ASSOC)){
print "<b>" . $row['name'] . "</b><br>";
print $row['code'] . "<br>";
print $row ['description'] . "<br>";
print $row['hours'] . " hrs. <br>";
print $row['semester'] . "<br>";
print $row['year'] . "<br>";
print "------------------------------<br />";
}
}
else
echo 'Could not fetch results.';
unset($pdo);
unset($query);
?>
当前输出
Computer Programming I
CPSC1400
Introduction to disciplined, object-oriented program development.
4 hrs.
Spring
2013
------------------------------
Computer Programming II
CPSC1500
This course builds upon the topics covered in Computer Science I and provides experience developing complex applications.
4 hrs.
Fall
2013
------------------------------
Database Programming
CPSC2100
Study of relational database management systems and information storage and retrieval techniques.
4 hrs.
Spring
2014
答案 0 :(得分:1)
您可以添加一个变量,例如$tothours
,然后在while
子句中添加$row['hours']
。
可能比sql语句中的另一个查询/连接更好。
示例强>
$tothours = 0;
while ($row = $query->fetch(PDO::FETCH_ASSOC)){
print "<b>" . $row['name'] . "</b><br>";
print $row['code'] . "<br>";
print $row ['description'] . "<br>";
print $row['hours'] . " hrs. <br>";
print $row['semester'] . "<br>";
print $row['year'] . "<br>";
print "------------------------------<br />";
$tothours += $row['hours']; <-- this line
}
print "<p>Total hours for Major: " . $tothours . ".</p>"
很抱歉,如果我的语法不正确。
答案 1 :(得分:1)
此查询显示按主要分组的课程时数总和:
select major.id, sum(course.hours)
from course, major, major_course_xref
where course.id = major_course_xref.course_id
and major.id = major_course_xref.major_id
group by major.id