Question

我有以下MongoDB对象：

 {
   "_id": ObjectId("508ec9f413f88da4a590e5ee"),
   "beersAndStouts": {
     "0": {
       "description": "Guinness",
       "price": "4.20"
    },
     "1": {
       "description": "Heineken",
       "price": "4.80"
    },
     "2": {
       "description": "Carlsberg",
       "price": "4.80"
    }
  },
   "snacks": {
     "0": {
       "description": "King cheese and onion",
       "price": "2.20"
    },
     "1": {
       "description": "Tayto cheese and onion",
       "price": "1.80"
    }
  },
   "specialOffers": {
     "0": {
       "description": "Two for one vodka\/red bull",
       "price": "8"
    }
  },
   "uname": "Eamorr",
   "wines": {
     "0": {
       "description": "Cabernet Sauvignon",
       "price": "5.00"
    },
     "1": {
       "description": "Chardonnay",
       "price": "5.00"
    }
  }
}

我有以下PHP变量：

$category=$_POST['category'];   //"beersAndStouts"
$description=$_POST['columnName'];   //"Description"
$value=$_POST['value'];   //"4.70"
$rowId=$_POST['rowId'];   //2

我想将嘉士伯（rowId = 2）的价格从4.80改为4.70 ......

如何运行这样的查询？

这就是我的声音，但我现在真的被困住了......

$priceLists=$mongo->eamorr->priceLists;
$priceLists->update(array('uname'=>$uname),array('$set'=>array($category=>array($rowId=>xxx))));

更新：这是我使用的代码：

$mongo=new Mongo();
$priceLists=$mongo->eamorr->priceLists;

$priceList=$priceLists->findOne(array('uname'=>$uname));

$newCategory=$priceList[$category];
$newCategory[$rowId][$description]=$value;

$priceLists->update(array('uname'=>$uname),array('$set'=>array($category=>$newCategory)));

它不漂亮，但它有效，我不需要改变我的结构。

Answer 1

为什么你需要它作为对象的对象？你可以用对象数组替换它，在这种情况下它可以正常工作这是一个想法：

{
  "_id" : ObjectId("508ec9f413f88da4a590e7ee"),
  "beersAndStouts" : [{
      "description" : "Guinness",
      "price" : "4.20"
    }, {
      "description" : "Heineken",
      "price" : 6666
    }, {
      "description" : "Carlsberg",
      "price" : "4.80"
    }],
  "snacks" : [{
      "description" : "King cheese and onion",
      "price" : "2.20"
    }, {
      "description" : "Tayto cheese and onion",
      "price" : "1.80"
    }],
  "specialOffers" : [{
      "description" : "Two for one vodka/red bull",
      "price" : "8"
    }],
  "uname" : "Eamorr",
  "wines" : [{
      "description" : "Cabernet Sauvignon",
      "price" : "5.00"
    }, {
      "description" : "Chardonnay",
      "price" : "5.00"
    }]
}

在这种情况下查询很简单：

db.test.update({
   "_id" : ObjectId("508ec9f413f88da4a590e7ee"),
   "beersAndStouts.description" : "Carlsberg"
},{
  '$set' : {
  'beersAndStouts.$.price' :  4.70
}
});

请记住我改变了ObjectId！

将它放在你的mongo shell中，它可以正常工作。

我希望将它调整为php是显而易见的。

MongoDB：坚持复杂查询...更新对象内的数组

1 个答案: