Question

我解决了1天的问题但是当我将这些日子分成1天时，我遇到了问题。

    declare @Start datetime
    declare @Finish datetime
    declare @TimeRange int

    set @Start = N'2012-10-16 00:00:00.000'
    set @Finish = N'2012-10-19 00:00:00.000'
    set @TimeRange = 1 

    declare @TimeRanges as TABLE (SessionStart datetime, SessionEnd datetime);

    with TimeRanges as 
    (   select @Start as StartTime, DATEADD(day, @TimeRange, @Start) as EndTime
        union all
        select DATEADD(day, @TimeRange, StartTime), DATEADD(day, @TimeRange, EndTime)
        from TimeRanges
        where EndTime  < @Finish 
    )

timeRanges表将@Start和@Finish分成几天。

以下是问题的开始：

 select StartTime, EndTime,TMP.NoOfCalls    
    from (SELECT TOP 1 DATEADD(SECOND, Number, c.SessionStartTime) CallTime, COUNT(C.ScenarioID) NoOfCalls FROM test c
INNER JOIN Numbers N ON N.Number <= DATEDIFF(SECOND, C.SessionStartTime, C.SessionCloseTime) 
where c.SessionStarttime >= @Start and  c.SessionCloseTime <= @Finish
GROUP BY DATEADD(SECOND, Number, c.SessionStartTime)
ORDER BY NoOfCalls DESC
)as TMP left outer join TimeRanges as TR on @Start <= TR.StartTime   and   TR.EndTime <= @Finish
        group by TR.StartTime, TR.EndTime,TMP.NoOfCalls
        order by TR.StartTime

以下是我得到的结果：

enter image description here

实际上260是N'2012-10-17 00：00：00.000'和N'2012-10-18 00：00：00.000'之间的结果，但我想分开结果。

我的样本测试表：

SessionID    SessionStartTime              SessionCloseTime
24       2012-10-16 01:00:06.000           2012-10-16 01:01:22.000
24       2012-10-16 01:00:08.000           2012-10-16 01:01:10.000
24       2012-10-16 01:00:16.000           2012-10-16 01:01:12.000
24       2012-10-16 01:00:30.000           2012-10-16 01:01:48.000
24       2012-10-16 01:00:41.000           2012-10-16 01:02:08.000
24       2012-10-16 01:00:48.000           2012-10-16 01:01:34.000
24       2012-10-16 01:00:56.000           2012-10-16 01:03:09.000
24       2012-10-16 01:01:02.000           2012-10-16 01:02:13.000
24       2012-10-16 01:01:05.000           2012-10-16 01:03:16.000
24       2012-10-16 01:01:09.000           2012-10-16 01:02:42.000
24       2012-10-16 01:01:15.000           2012-10-16 01:02:48.000
24       2012-10-16 01:01:18.000           2012-10-16 01:02:14.000
24       2012-10-16 01:01:18.000           2012-10-16 01:02:06.000
24       2012-10-16 01:01:42.000           2012-10-16 01:03:16.000
24       2012-10-16 01:01:45.000           2012-10-16 01:03:04.000

Answer 1

您的问题是左连接，但您的查询似乎过于复杂。

尝试

   with TimeRanges as 
    (   select @Start as StartTime, DATEADD(day, @TimeRange, @Start) as EndTime
        union all
        select DATEADD(day, @TimeRange, StartTime), DATEADD(day, @TimeRange, EndTime)
        from TimeRanges
        where EndTime  < @Finish 
    )
        select TimeRanges.StartTime, TimeRanges.EndTime, COUNT(*)
        from TimeRanges
            inner join YourTable Sess
                on sess.sessionstarttime>TimeRanges.StartTime 
                and sess.sessionclosetime< TimeRanges.EndTime
        group by TimeRanges.StartTime, TimeRanges.EndTime

TSQL DateRange日复一日计算

1 个答案: