Question

我需要在SQL Server中查询以下格式的一些数据：

Id Group Price
1 A 10
2 A 20
Sum 30
1 B 6
2 B 4
总和10
1 C 100
2 C 200
Sum 300

我想在以下几个步骤中做到这一点：

查询一个小组
在其他查询中求和
使用Union运算符组合此结果集
对所有组执行步骤1-3，最后使用union返回所有子数据集。

有更好的方法吗？可能正在使用一些开箱即用的功能？请指教。

修改

根据建议和代码示例，我尝试了这段代码：

Select 
Case 
when id is null then 'SUM' 
else CAST(id as Varchar(10)) end as ID,

Case when [group] is null then 'ALL' else CAST([group] as Varchar(50)) end as [group]
,Price from
(
SELECT Id,  [Group],BGAApplicationID,Section, SUM(PrimaryTotalArea) AS price   
FROM vwFacilityDetails
where bgaapplicationid=1102
GROUP BY Id,  [Group],BGAApplicationID,Section  WITH ROLLUP
) a

甚至这个代码也是如此：

Select Id,  [Group],BGAApplicationID,Section, SUM(PrimaryTotalArea) AS price           
From   vwFacilityDetails
Where  Not ([group] Is Null And id Is Null And BGAApplicationId is null and section is null) and BGAApplicationId=1102
Group By Id,  [Group],BGAApplicationID,Section 
    With Rollup

在结果中，它对数据进行分组，但对于每个记录，它显示3次（在上述两个代码中），如：

2879现有设施全校25.00
2879现有设施全校25.00
2879现有设施全校25.00
2879 ALL 25.00

我想我的查询中存在一些问题，请在这里指导我。感谢

Answer 1

Select
  id,
  [Group],
  SUM(price) AS price
From
  Test
Group By
  [group],
  id 
With
  Rollup

http://sqlfiddle.com/#!3/080cd/8

Answer 2

SQL Server引入了GROUPING SETS，这是您应该使用的内容。

SQL Fiddle

MS SQL Server 2008架构设置：

Create Table vwFacilityDetails (
  id int not null,
  [group] char(1) not null,
  PrimaryTotalArea int not null,
  Section int,
  bgaapplicationid int
);

Insert Into vwFacilityDetails (id, [group], Section,bgaapplicationid,PrimaryTotalArea) values
  (1, 'A', 1,1102,2),
  (1, 'A', 1,1102,1),
  (1, 'A', 1,1102,7),
  (2, 'A', 1,1102,20),
  (1, 'B', 1,1102,6),
  (2, 'B', 1,1102,4),
  (1, 'C', 1,1102,100),
  (2, 'C', 1,1102,200);

查询1 ：

SELECT CASE WHEN Id is null then 'SUM'
            ELSE Right(Id,10) end Id,
       [Group],BGAApplicationID,Section,
       SUM(PrimaryTotalArea) price   
FROM vwFacilityDetails
where bgaapplicationid=1102
GROUP BY GROUPING SETS (
  (Id,[Group],BGAApplicationID,Section),
  ([Group])
)
ORDER BY [GROUP],
         ID;

<强> Results ：

|  ID | GROUP | BGAAPPLICATIONID | SECTION | PRICE |
----------------------------------------------------
|   1 |     A |             1102 |       1 |    10 |
|   2 |     A |             1102 |       1 |    20 |
| SUM |     A |           (null) |  (null) |    30 |
|   1 |     B |             1102 |       1 |     6 |
|   2 |     B |             1102 |       1 |     4 |
| SUM |     B |           (null) |  (null) |    10 |
|   1 |     C |             1102 |       1 |   100 |
|   2 |     C |             1102 |       1 |   200 |
| SUM |     C |           (null) |  (null) |   300 |

Answer 3

Select Case when id is null then 'SUM' else CAST(id as Varchar(10)) end as ID
,Case when [group] is null then 'ALL' else CAST([group] as Varchar(10)) end as [group]
,Price from
(
SELECT id, [group], SUM(price) AS Price
FROM IG
GROUP BY [GROUP],ID WITH ROLLUP
) a

在开始下一组之前查询总行数据组？

3 个答案: