Question

这就是我所拥有的，但这只生成一次随机数并无限打印该数字：

import random

x = random.randint(0,10)
y = 7
while x != y:
    print(x)

Answer 1

像（在一段时间内移动条件）：

stop_at = 7
while True:
    num = random.randint(0, 10)
    if num == stop_at:
        break
    print num

或者，一个完整的因素：

from itertools import starmap, repeat, takewhile
from random import randint

for num in takewhile(lambda L: L != 7, starmap(randint, repeat( (0, 10) ))):
    print num

Answer 2

你差不多了，你需要在循环中生成一个新的随机数：

import random

x = random.randint(0,10)
y = 7
while x != y:
    print(x)   #Print old (non-7) random number
    x = random.randint(0,10)  #pick a new number.  I hope it's 7 so we can end this madness

print("You found {0}.  Congrats.  Go have a beer.".format(y))

while循环打印1到10之间的随机数，当数字为N时停止

2 个答案: