如何输出结果？

Question

  

可能重复：
  Able to see a variable in print_r()'s output, but not sure how to access it in code

print_r($node)的输出如下。

[field_pimage] => Array
        (
            [und] => Array
                (
                    [0] => Array
                        (
                            [fid] => 4
                            [alt] => 
                            [title] => 
                            [width] => 1440
                            [height] => 900
                            [uid] => 1
                            [filename] => 200801232112524201.jpg
                            [uri] => public://200801232112524201.jpg
                            [filemime] => image/jpeg
                            [filesize] => 122349
                            [status] => 1
                            [timestamp] => 1351403970

我想输出[uri]的值，我应该怎么做？

 $node->field_pimage->und->0->['uri'];  //but it doesn't work?

Answer 1

您正在处理数组，而不是对象。

所以你需要$node->field_pimage['und'][0]['uri']（如果$node本身是一个对象）或$node['field_pimage']['und'][0]['uri']（如果$node也是一个数组）

Answer 2

因为它是一个数组......应该使用...

来访问它

$node['field_pimage']['und'][0]['uri'];

Answer 3

echo $node["field_pimage"]["und"]["0"]["uri"];

Answer 4

由于它们都是数组，因此您可以使用此语法;

$node['field_pimage']['und'][0]['uri'];

Answer 5

这是一个多维数组。

处理数组的层次结构。

$uri = $node['field_pimage']['und'][0]['uri'];

print($uri);