Question

我正在开发一个小应用程序，我试图从网站上读取一些文本，将文本存储在变量中，然后在另一个活动中显示该文本。在我的主要活动中，我有一个名为“许可协议”的可点击标签，点击后，应用程序应该从网站读取一些文本，转到另一个活动，然后为用户显示该文本。但是，每次我点击我的标签时，我的app力都会关闭。有什么建议？

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;


import android.os.Bundle;
import android.app.Activity;
import android.content.Intent;
import android.view.Menu;
import android.view.View;

public class MainActivity extends Activity {

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        getMenuInflater().inflate(R.menu.activity_main, menu);
        return true;
    }

    public void activity_license(View view) throws IOException{


        String stringBuffer;
        String text ="";

        URL url = new URL("http://something.something.com/LICENSE");

        BufferedReader bufferReader = new BufferedReader(new InputStreamReader(url.openStream()));

        while((stringBuffer = bufferReader.readLine()) != null){
            text += stringBuffer;
        }

        bufferReader.close();

        Intent licenseIntent = new Intent(this, LicenseActivity.class);
        licenseIntent.putExtra("LICENSE_AGREEMENT", text);
        startActivity(licenseIntent);
    }
}

这是我的第二个活动代码，我想要显示文本......

import android.os.Bundle;
import android.app.Activity;
import android.content.Intent;
import android.view.Menu;
import android.widget.TextView;

public class LicenseActivity extends Activity {

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_license);

        Intent intent = getIntent();

        String licenseText = intent.getStringExtra("LICENSE_AGREEMENT");

        TextView lblText = (TextView)findViewById(R.id.lblLicense);
        lblText.setText(licenseText);
    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        getMenuInflater().inflate(R.menu.activity_license, menu);
        return true;
    }
}

Answer 1

// RETRIVE YOUR RESPONSE 
    try 
    {
        BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) 
        {
            sb.append(line + "\n");
        }
        is.close();
        result = sb.toString();
    }
    catch (Exception e) 
    {   
        Log.e("Loading Runnable Error converting result :", e.toString());
    }

现在将此结果打印为字符串。

Answer 2

试试这个

DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(URL);

HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();

InputStream is = httpEntity.getContent();
StringBuilder text = new StringBuilder();
BufferedReader br = new BufferedReader(new InputStreamReader(is));
String line;
while ((line = br.readLine()) != null) {
    text.append(line + "\n");
}

try 
    intent.putExtra("licence",text.toString);

如果这不起作用，请尝试 HttpGet 代替 HttpPost ......

在Android应用中从URL读取文本的困难

2 个答案: