使用模型中的函数

Question

Users.php（型号）：

...
public function hashPassword($password){
    $hashed = hash('sha256', $password . self::HASH_CODE);
    return $hashed;
}
...

UserIdentity.php

...
else if($user->password!==Users::hashPassword($this->password))
...

错误：

Non-static method Users::hashPassword() should not be called statically, assuming $this from incompatible context

Answer 1

您需要将hashPassword()定义为静态函数才能使用Users::hashPassword()调用它：

public static function hashPassword($password) {
    ...

否则，您可以创建Users类的实例并以非静态方式调用它：

$users = new Users();
$users->hashPassword($password);

严格来说 - yii意义上，您可以使用以下内容进行调用（具体取决于您的设置）：

Yii::app()->Users->hashPassword($password);

Answer 2

else if($user->password!==Users::model()->hashPassword($this->password))

这不是静态方法

Answer 3

创建函数static

public static function hashPassword($password){
    $hashed = hash('sha256', $password . self::HASH_CODE);
    return $hashed; }