Question

如果表格中有2个日期列，startDate和endDate。如何返回给定日期适合这两个日期的行？例如：

如果给定日期为2012-10-25

它应该返回以下行

startDate   -   endDate
2012-10-25  -   2012-10-25
2011-09-10  -   2013-11-15
2012-10-20  -   2012-10-25
2012-10-23  -   2012-10-28
2012-09-14  -   2012-10-28

来自以下行：

startDate   -   endDate
2012-10-25  -   2012-10-25
2011-09-10  -   2013-11-15
2012-01-11  -   2012-10-11
2012-10-20  -   2012-10-25
2012-04-15  -   2012-04-16
2012-05-20  -   2012-05-25
2012-12-01  -   2012-12-10
2012-10-23  -   2012-10-28
2012-09-14  -   2012-10-28
2012-11-13  -   2012-12-15

这可以用sql吗？

我正在使用sql server 2008。

Answer 1

使用SQL Server，它实际上就像：

一样简单

SELECT startDate, endDate
FROM YourTable
WHERE '2012-10-25' between startDate and endDate

Answer 2

检查BETWEEN关键字。

语法很简单：

SELECT col1, col2
FROM table1
WHERE date_col BETWEEN '2012-10-25' and 2012-10-28

Answer 3

对于其他lappingcheck，以下可能很有趣

Select * from sted where [dbo].[F_LappingDays](Startdate,EndDate,'20121025','20121025')=1


CREATE Function [dbo].[F_LappingDays](@Von1 datetime,@bis1 Datetime,@von2 Datetime,@bis2 Datetime) Returns int as
/*
20110531 Thomas Wassermann
Terminüberschneidungen finden
*/
begin
Declare @Result int

Select @Result  = 0
if (@Von1>=@Von2) and (@bis1<=@Bis2)
    begin
        Select @Result=Cast(@Bis1 - @von1 + 1 as Int)
    end

else if (@Von1<=@Von2) and (@bis1 > @Von2) and (@bis1<=@Bis2)
    begin
        Select @Result=Cast(@Bis1 - @von2 + 1 as Int)
    end

else if (@Von1>=@Von2) and (@von1<=@bis2) and (@bis1>@Bis2)
    begin
        Select @Result=Cast(@Bis2 - @von1 + 1 as Int)
    end

else if (@Von1<@Von2) and (@bis1>@Bis2)
    begin
        Select @Result=Cast(@Bis2 - @von2 + 1 as Int)
    end



Return @Result
end

Answer 4

您可以使用 between 运算符来查找两个约束之间的值。这对于查找范围内的日期也很有用。

SELECT startDate, endDate FROM sampleTable WHERE '2012-10-25' between startDate and endDate

了解更多BETWEEN

检查给定日期是否适合一系列日期

4 个答案: