将值拆分为多行

时间:2012-10-31 13:50:16

标签: sql sql-server sql-server-2008 stored-procedures

  

可能重复:
  Turning a Comma Separated string into individual rows

我从存储过程得到以下输出,并想知道将值拆分为多行的最佳方法。

reference   name                            subjects       subjectstitle
LL9X81MT    Making and Decorating Pottery   F06,F27,F38       NULL

我需要修剪逗号的subject字段并将信息复制三行,以便数据如下。

reference   name                            subjects       subjectstitle
LL9X81MT    Making and Decorating Pottery   F06       NULL
LL9X81MT    Making and Decorating Pottery   F27       NULL
LL9X81MT    Making and Decorating Pottery   F38       NULL

我正在使用MS SQL Server 2008来设置这些SP,并且需要一些关于如何拆分主题字段的帮助。

谢谢,

2 个答案:

答案 0 :(得分:15)

您将需要使用某种类似于此的表值拆分函数:

create FUNCTION [dbo].[Split](@String varchar(MAX), @Delimiter char(1))       
returns @temptable TABLE (items varchar(MAX))       
as       
begin      
    declare @idx int       
    declare @slice varchar(8000)       

    select @idx = 1       
        if len(@String)<1 or @String is null  return       

    while @idx!= 0       
    begin       
        set @idx = charindex(@Delimiter,@String)       
        if @idx!=0       
            set @slice = left(@String,@idx - 1)       
        else       
            set @slice = @String       

        if(len(@slice)>0)  
            insert into @temptable(Items) values(@slice)       

        set @String = right(@String,len(@String) - @idx)       
        if len(@String) = 0 break       
    end   
return 
end;

然后,您可以使用outer apply加入yourtable:

select t1.reference,
  t1.name,
  t1.subjectstitle,
  i.items subjects
from yourtable t1
outer apply dbo.split(t1.subjects, ',') i

给出这样的结果:

| REFERENCE |                          NAME | SUBJECTSTITLE | SUBJECTS |
------------------------------------------------------------------------
|  LL9X81MT | Making and Decorating Pottery |        (null) |      F06 |
|  LL9X81MT | Making and Decorating Pottery |        (null) |      F27 |
|  LL9X81MT | Making and Decorating Pottery |        (null) |      F38 |

请参阅SQL fiddle with Demo

如果你想在没有分割功能的情况下这样做,那么你可以使用CTE:

;with cte (reference, name, subjectstitle, subjectitem, subjects) as
(
  select reference,
    name,
    subjectstitle,
    cast(left(subjects, charindex(',',subjects+',')-1) as varchar(50)) subjectitem,
         stuff(subjects, 1, charindex(',',subjects+','), '') subjects
  from yourtable
  union all
  select reference,
    name,
    subjectstitle,
    cast(left(subjects, charindex(',',subjects+',')-1) as varchar(50)) ,
    stuff(subjects, 1, charindex(',',subjects+','), '') subjects
  from cte
  where subjects > ''
) 
select reference, name, subjectstitle, subjectitem
from cte

请参阅SQL Fiddle with Demo

答案 1 :(得分:9)

这将没有分割功能

SELECT T1.reference, T1.name, T2.my_Splits AS subjects, T1.subtitile
FROM
 (
  SELECT *,
  CAST('<X>'+replace(T.subjects,',','</X><X>')+'</X>' as XML) as my_Xml 
  FROM [yourTable] T
 ) T1
 CROSS APPLY
 ( 
 SELECT my_Data.D.value('.','varchar(50)') as my_Splits
 FROM T1.my_Xml.nodes('X') as my_Data(D)
 ) T2