我有一个信息框来显示事件的数量:
我有一个功能:
function getStateCounts()
{
$query = sprintf("select t1.count, t2.State_name
from (select count(*) as count, state
from INC_DIST_SUMMARY S
join SHAPE_LAYERS L on L.geo_id = S.shape_geo_id
group by state) as t1, SHAPE_LAYER_STATE_DESC as t2
where t1.state=t2.state");
$count = mysql_query($query);
if (!$count) {
echo "<error> Invalid query " . $query . "</error>"
die("Invalid query: " . mysql_error());
}
return $count;
}
我必须将输出查询结果存储在“No of Thidents”中;
while ($item = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo "<item><title geoid='" . $item['GEO_ID'] . "'>" .
$item['STATE_NAME']."(".($item['STATE_ABBR']).")" .
"</title><description cong_dist='".$item['DIST_NAME']."'>";
echo $item['STATE_ABBR'] . $item['DIST_NAME'] . " <br/>";" **No of Incidents:";**
echo $item['INC_COUNT'] . "</description>";
echo "</item>"
我必须将此事件值修复为“No of Thidents”:
while ($item = mysql_fetch_array($count, MYSQL_ASSOC)) {
echo "<summary>";
echo "<state>".$count['STATE']."</state>";
echo "<count>".$count['COUNT']."</count>"
echo "</summary>";
}
如何在“No of Tridents”变量中显示查询值?
答案 0 :(得分:1)
在非COUNT(*)查询上执行rowCount();
标记您使用$ rowscounted的任何技术的结果并替换
if (!$count) {
echo "<error> Invalid query " . $query . "</error>";
die("Invalid query: " . mysql_error());
}
return $count;
}
使用:
if ($rowscounted == 0) {
echo "<error> Invalid query " . $query . "</error>";
die("Invalid query: " . mysql_error());
}
else {
echo '$rowscounted states were returned by your query.'
}
我是php的新手,所以也许不是最好的答案,但我最近自己做了一个这样的问题,并认为这对你有用。 (作为一个新手,拿一小撮盐,哦,哈希,如果你愿意......)