为什么int不会改变? java的

时间:2012-10-31 02:59:57

标签: java

有人可以告诉我如何在以下代码中获取int x的值: 当我左右移动方格时,Test的输出保持为500。

我希望Thread in Test在每次循环时获取x的值,但x总是500(来自线程),即使x的值在Drawing.java中发生了变化。请帮帮我。

package block;


public class Test extends Drawing implements Runnable{
Thread collision = new Thread(this);

public Test() {
    collision.start();
}

@Override
public void run() {

    while(true) {
        System.out.println(x);
    }
}

}

package block;

import java.awt.Canvas;
import java.awt.Color;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.event.KeyEvent;
import java.awt.event.KeyListener;
import java.util.logging.Level;
import java.util.logging.Logger;


public class Drawing extends Canvas implements Runnable, KeyListener{
Thread thread = new Thread(this);

int x = 500;
int y = 540;
public Drawing() {        
    setSize(1000, 800);
    addKeyListener(this);
    thread.start();
}

public void update(Graphics g) {
    g.setColor(Color.WHITE);
    g.fillRect(0, 0, 1000, 700);
    paint(g);
}

public void paint(Graphics g) {
    g.setColor(Color.cyan);
    g.fillRect(x, y, 50, 50);
}

@Override
public void run() {
    while(true) {
        repaint();
        try {
            Thread.sleep(100);
        } catch (InterruptedException ex) {
            Logger.getLogger(Drawing.class.getName()).log(Level.SEVERE, null, ex);
        }

    }

}

@Override
public void keyTyped(KeyEvent ke) {

}

@Override
public void keyPressed(KeyEvent ke) {
    if(ke.getKeyCode() == KeyEvent.VK_LEFT) {
        x -= 5;
    }
    if(ke.getKeyCode() == KeyEvent.VK_RIGHT) {
        x += 5;
    }
}

@Override
public void keyReleased(KeyEvent ke) {

}

}

编辑:--------------------

package block;

import javax.swing.JFrame;


public class Block extends JFrame{

    Test test = new Test();

    public Block() {
        setSize(1000, 700);
        setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        setLocationRelativeTo(null);        
        add(new Drawing());        
        setVisible(true);
        createBufferStrategy(2);
    }

    public static void main(String[] args) {
        new Block();
    }
}

1 个答案:

答案 0 :(得分:2)

您正在创建x的多个实例,因为您没有正确使用继承。当您致电new Test()时,会创建Test的一个实例(其中包含Drawing,其中包含成员x),然后调用{{1} }创建new Drawing()的另一个实例(其中包含不同的成员Drawing)。

要解决此问题,您可以将引用传递给x构造函数的Drawing对象,并通过引用访问Test成员。< / p>