Question

我有一个二维数组：

$test = array(
    "foo" => array(
        'a' => 1,
        'b' => 2,
        'c' => 3
    ),
    "bar" => array(
        'a' => 1,
        'b' => 2,
        'c' => 3
    ),
    "baz" => array(
        'a' => 1,
        'b' => 2,
        'c' => 3
    )
);

我想在外部数组的每个元素中添加一个名为'd'且值为4的字段，以便生成的数组变为：

array(
    "foo" => array(
        'a' => 1,
        'b' => 2,
        'c' => 3,
        'd' => 4
    ),
    "bar" => array(
        'a' => 1,
        'b' => 2,
        'c' => 3,
        'd' => 4
    ),
    "baz" => array(
        'a' => 1,
        'b' => 2,
        'c' => 3,
        'd' => 4
    )
)

我试过这个：

foreach ( $test as $elem ) 
{
    $elem['d'] = 4;
}

哪个不起作用。我做错了什么，我怎样才能做到这一点？

Answer 1

数组和基元在PHP中通过值传递（尽管对象通过引用传递）。在foreach循环中克服此问题的一种方法是通过循环中的引用访问子数组：

// Call $elem by reference with &
foreach ( $test as &$elem ) {
    $elem['d'] = 4;
}

print_r($test);
array(3) {
  ["foo"]=>
  array(4) {
    ["a"]=>
    int(1)
    ["b"]=>
    int(2)
    ["c"]=>
    int(3)
    ["d"]=>
    int(4)
  }
  ...
}

Answer 2

$test = array(
    "foo" => array(
        'a' => 1,
        'b' => 2,
        'c' => 3
    ),
    "bar" => array(
        'a' => 1,
        'b' => 2,
        'c' => 3
    ),
    "baz" => array(
        'a' => 1,
        'b' => 2,
        'c' => 3
    )
);

foreach($test as $key => $val)
    $test[$key]['d'] = 4;

print_r($test);

Answer 3

你可以利用php函数和回调：

array_walk($test, function ( & $value) {                                                                                                                                                            
     $value['d'] = 4;
});

无法在foreach中向数组添加新字段

3 个答案: