我一直在寻找所有地方,但我能找到的只是初始化结构数组的东西,而不是另一个函数。这是我的旧作业。我的任务是从文本文件中读取命令,将它们存储到数组中并将命令传递到名为sketchpad的程序中。我实际上觉得我应该在另一个函数中初始化/重新初始化我的struct数组,因为在文本文件中有一个end命令(我认为在该end命令之后没有任何内容)。仔细看看,我忘了满足于你可以连续读取两个文本文件的事实。还有其他方法,教师在课堂上向我们展示了迎合它的方式。但我想知道如何按照我的方式去做。您如何调用初始化/重新初始化结构数组并将值发送回调用它的函数的函数?我们用指针吧?我们将如何去做呢?
这是我的代码:
void fileParsing(FILE * fp, FILE* pipe)
{
/*defines and initializes the commands being searched and counted */
int Figure =0;
int draw =0;
int End =0;
int printFigure =0;
int drawFigure =0;
int translate =0;
int child =0;
int comment =0;
int i, j;
struct figure array_figure[19]; //WTF!!!! WHY 19?????
//assigns absurd values to array to distinguish when to stop looking for coordinates
for(i=0; i < FIGURE_MAX; ++i)
{
memset(array_figure[i].name, 0, LINE_LEN);
for(j=0; j<POINTS_MAX; ++j)
{
array_figure[i].Coord[j].xcoor = fup_value;
array_figure[i].Coord[j].ycoor =fup_value;
}
}
//array_figure[15].name = "adsfsdf";
//printf("\n%d",array_figure[0].Coord[0].xcoor);
int count = 0;
int count2 = 0;
int drawCount = 0;
int reset;
//if(reset = 0; reset < 256; reset++);
//strncpy(array_figure[count].name, "0", LINE_LEN);
//printf("about to go into a while loop\n");
while(fgets(line, LINE_LEN, fp)!=NULL)
{
sscanf(line, "%s%s%d%d", command, name, &x, &y);
//looks for commands and organizes them accordingly
if(strncmp(command, "Figure", 6) == 0)
{
printf("Found a Figure command\n");
sscanf(line, "%s%s%d%d", command, name, &x, &y);
originX = x;
originY = y;
//assigns name and initial point
strncpy(array_figure[count2].name, name, LINE_LEN);
array_figure[count2].Coord[count].xcoor = x; //change: count2 from '3' from array_figure[i]
array_figure[count2].Coord[count].ycoor = y;
//printf("%s: %lf, %lf\n", array_figure[count2].name, array_figure[count2].Coord[count].xcoor, array_figure[count2].Coord[count].ycoor);
count++;
//printf("%d\n", count);
//fprintf(output, "%d %d\n", x, y); //MIGHT BE NEEDED!
//originX = x;
//originY = y;
}
else if(strncmp(command, "draw", 5) == 0)
{
printf("Found a draw command\n");
sscanf(line, "%s%d%d", command, &x, &y);
//strncpy(array_figure[count].name, "0", LINE_LEN);
//priFiguntf("%s\n", array_figure[2].name);
//creates a new origin coordinate
originX = array_figure[count2].Coord[count-1].xcoor;
originY = array_figure[count2].Coord[count-1].ycoor;
//assigns more coordinates
array_figure[count2].Coord[count].xcoor = originX + x;
array_figure[count2].Coord[count].ycoor = originY + y;
//printf("%lf, %lf\n", array_figure[count2].Coord[count].xcoor, array_figure[count2].Coord[count].ycoor);
//printf("%c\n", array_figure[count]);
count++;
//printf("%d\n", count);
}
else if(strncmp(command, "drawFigure", 10) == 0)
{
printf("Found a drawFigure command\n");
sscanf(line,"%s%s\n", command, name);
//if statement; iterates through to with strncmp to find figure name to draw
//printf("%s\n", name);
drawFigureCount= 0;
//checks for which element matchs the specified name for drawing
while(
strncmp(array_figure[drawFigureCount].name, name, LINE_LEN) != 0 &&
drawFigureCount < FIGURE_MAX)
drawFigureCount++;
if(drawFigureCount < FIGURE_MAX)
{
//printf("\tstartingX/Y assign\n");
startingX = array_figure[drawFigureCount].Coord[0].xcoor;
startingY = array_figure[drawFigureCount].Coord[0].ycoor;
//printf("\tdone - startingX/Y assign\n");
//sends coordinates to sketchpad
for(i=1; i< POINTS_MAX; ++i)
{
if(array_figure[drawFigureCount].Coord[i].xcoor != fup_value &&
array_figure[drawFigureCount].Coord[i].ycoor != fup_value)
{
//printf("\t\tdraw segment sent to output\n");
fprintf(pipe,
"drawSegment %ld %ld %ld %ld\n",
lround(startingX), lround(startingY),
lround(array_figure[drawFigureCount].Coord[i].xcoor),
lround(array_figure[drawFigureCount].Coord[i].ycoor)
);
//printf("\t\tdone - draw segment sent to output\n");
//printf("\t\tstartingX/Y update\n");
startingX = array_figure[drawFigureCount].Coord[i].xcoor;
startingY = array_figure[drawFigureCount].Coord[i].ycoor;
//printf("\t\tdone - startingX/Y update\n");
} else break;
}
//printf("\tbroke out of the loop or the loop ended\n");
}
}
//checks for "end" in the input file to know when to stop making coordinates for a figure
else if(strncmp(command, "End", 3) == 0)
{
printf("Found a End command\n");
//strncpy(array_figure[count].name, command, LINE_LEN);
//printf("%s\n", array_figure[count].name);
count2++;
count = 0;
}
//organizes and prints coordinates to console
else if(strncmp(command, "printFigure", 11) == 0)
{
//printf("Print Figure %s\n", name); **UNCOMMENT**
while(strncmp(array_figure[printFigureCount].name, name, LINE_LEN) != 0 &&
printFigureCount < FIGURE_MAX)
printFigureCount++;
if(printFigureCount < FIGURE_MAX)
{
for(i=0; i< POINTS_MAX; ++i)
{
if(array_figure[printFigureCount].Coord[i].xcoor != fup_value &&
array_figure[printFigureCount].Coord[i].ycoor != fup_value)
{
//converts values to int for printing
int intConvertX = (int) array_figure[printFigureCount].Coord[i].xcoor;
int intConvertY = (int) array_figure[printFigureCount].Coord[i].ycoor;
//printf("%d %d\n", intConvertX, intConvertY); **UNCOMMENT**
}
}
}
}
else if(strncmp(command, "translate", 9) == 0)
{
printf("Found a Translate command\n");
//translate++;
}
/*else if(strncmp(command, "clearScreen", 11) == 0)
{
sscanf(line, "%s%s", command, clear);
printf("%s\n", clear);
}*/
else if(strncmp(command, "child", 5) == 0)
{
sscanf(line, "%s%s", command, clear);
printf("Found a child command\n");
//printf("\t\t\tsending child\n");
fprintf(pipe, "%s", &line[5]);
printf("passed fprintf\n");
if(strncmp(clear, "clearScreen", 11) == 0)
{
printf("%s\n", clear);
fprintf(pipe, "%s", &clear[11]);
break;
}
//printf("\t\t\tdone -- sending child\n");
}
else if(strncmp(command, "#", 1) == 0)
{
printf("Found a # command\n");
//printf("%s", line); **COMMENT OUT**
}
}
如果您在说出"clearScreen"
时发出通知,它将在{0}文本文件中显示为"child clearScreen"
,if(strncmp(clear, "clearScreen", 11) == 0)
。我之后打破了它,但是我想让它调用另一个函数来重新初始化一个数组,所以我不必离开这个函数。
答案 0 :(得分:2)
取决于“初始化”的含义。
如果您将struct数组声明为
struct figure array_figure[19];
并且您只是想将元素的所有值设置回默认值,然后您可以将数组传递给函数并在函数内修改它(从技术上讲,您将指针传递给第一个元素)。这种功能的签名可能如下所示:
void modify(struct figure *array_of_structs, unsigned int length_of_array)
并按如下方式调用:
modify(array_figure, 19); // if 19 is the length, that is
如果你想要一个全新的数组,那么你必须按照Jonathan Cruz的建议分配一个新数组。
答案 1 :(得分:0)
要初始化,请使用malloc分配所需的内存。 malloc返回一个指针,以便您可以将其放入函数中。如果你想重新初始化,你可以释放结构并重新进行。
类似的东西:
typedef struct mystruct {
// ...
}MyStruct;
MyStruct* getMyStruct() {
return (MyStruct*) malloc(sizeof(MyStruct));
}
检查那些可能有帮助的链接。