当我退出应用程序时,为什么会出现应用程序崩溃?

时间:2012-10-30 20:00:47

标签: java android

我遇到以下简单代码的问题。我创建了SurfaceView类,它扩展了SurfaceView。我在另一个从onCreate方法开始的线程上运行它:

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate( savedInstanceState );
    GraphicView v = new GraphicView( this );
    Thread thread = new Thread( v );
    thread.start();
    setContentView( v );    
}

我不知道为什么但是当我关闭我的应用程序时 - 我收到错误。我不在我的平板电脑上使用英文UI,但我认为英文听起来像这样:“应用程序中出现错误”。仅此而已!也许我需要停止线程?我的代码中是否有错误?

public class GraphicView extends SurfaceView implements Runnable {

    Activity activity;
    SurfaceHolder holder;
    Paint paint;

    public GraphicView( Activity activity ) {

        super( activity );      

        this.activity = activity;

        paint = new Paint(); 
        paint.setColor( Color.YELLOW ); 
        paint.setStyle( Style.FILL ); 

        holder = getHolder();

    }

    @Override
    public boolean onTouchEvent( MotionEvent me ) {
        return false;
    }

    public void run() {

        while ( true ) {

            if ( !holder.getSurface().isValid() ) {
                continue;
            }

            Canvas c = holder.lockCanvas();
            c.drawARGB( 255, 128, 255, 80 );
            holder.unlockCanvasAndPost( c );

        }

    }

}

所以错误是:

10-31 00:02:20.124: W/KeyCharacterMap(278): No keyboard for id 0
10-31 00:02:20.124: W/KeyCharacterMap(278): Using default keymap: /system/usr/keychars/qwerty.kcm.bin
10-31 00:02:21.104: W/dalvikvm(278): threadid=11: thread exiting with uncaught exception (group=0x4001d800)
10-31 00:02:21.124: E/AndroidRuntime(278): FATAL EXCEPTION: Thread-10
10-31 00:02:21.124: E/AndroidRuntime(278): java.lang.NullPointerException
10-31 00:02:21.124: E/AndroidRuntime(278):  at com.example.GraphicView.run(GraphicView.java:192)
10-31 00:02:21.124: E/AndroidRuntime(278):  at java.lang.Thread.run(Thread.java:1096)

GraphicView.java的第192行:

c.drawARGB( 255, 128, 255, 80 );

1 个答案:

答案 0 :(得分:1)

尝试用while(!yourActivity.isFinishing())

替换while(true)

也许更好的是你应该在Activity的onPause中打破你的循环并在onResume()中恢复它