php函数中出现意外输出

时间:2012-10-30 18:08:27

标签: php function

这是我在PHP上做的一个简单的函数。问题在于它提供了完全未预料到的输出。

从我的数据库中,它需要$ takings = 242和$ cost = 81所以它应该显示242-81 = 161作为答案。但相反它显示242.可能是什么问题?

function differences($takings,$cost)
{
$difference = $takings - $cost;

if($difference < 0)
{
    $color = red;
    $difference = '$'.$difference.'million';
}

elseif($difference > 0)
{
   $color = green;
   $difference = '$'.$difference.='million';
}   

elseif($difference = 0)
{
   $color = blue;
   $difference = "broken even ";
}

return '<span style="color:'.$color.';">'.$difference.'</span>';
}

专家。这是该页面的完整代码。在浏览器中打开页面时,会显示以下内容:enter image description here

<?php

function getdirector($director)
{
global $db;
$query = 'select name from peopledb where peopleid = '.$director;
$result = mysql_query($query) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
extract($row);
return $name;
}

function getactor($actor)
{
$query = 'select name from peopledb where peopleid = '.$actor;
$result = mysql_query($query) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
extract($row);
return $name;
}


function getmovietype($type)
{
$query = 'select movietype from movietype where movieid = '.$type;
$result = mysql_query($query) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
extract($row);
return $movietype;
}


function differences($takings,$cost)
{
$difference = $takings - $cost;

if($difference < 0)
{
    $color = red;
    $difference = '$'.$difference.'million';
}

elseif($difference > 0)
{
   $color = green;
   $difference = '$'.$difference.='million';
}   

elseif($difference = 0)
{
   $color = blue;
   $difference = "broken even ";
}

return '<span style="color:'.$color.';">'.$difference.'</span>';
}


$abc = $_GET['movieid'];


$db = mysql_connect('localhost','root','saw123') or die('Connection error');
mysql_select_db("moviesite",$db) or die(mysyql_error($db));
$query = "select moviename,releaseyear,director,actor,type,movierunningtime,moviecost,movietakings from movie where movieid = ". $abc;




$result = mysql_query($query,$db) or die(mysql_error($db));

$row = mysql_fetch_assoc($result);
$movie_name = $row['moviename'];
$movie_director = getdirector($row['director']);
$movie_releaseyear = $row['releaseyear'];
$movie_actor = getactor($row['actor']);
$movie_type = getmovietype($row['type']);
$movie_runningtime = $row['movierunningtime'].' minutes';
$movie_cost =$row['moviecost'].'million';
$movie_takings = $row['movietakings'].'million';
$movie_health = differences($row['movietakings'],$row['movie_cost']);



echo <<<ENDHTML
<html>
 <head>
   <title> Details and Reviews for the movies for $movie_name </title>
  </head>
<body>
<div style="text-align: center;">
<h2>$movie_name</h2>
<h3> details </h3>
<table cellpadding = "1" cellspacing = "4"
style = "width = 80% ;margin-left: auto;margin-right: auto;";>
<tr>
 <td><strong>Title</strong></strong></td>
 <td>$movie_name</td>
</tr>

<tr>
 <td><strong>release date</strong></strong></td>
 <td>$movie_releaseyear</td>
</tr>
<tr>

<tr>
 <td><strong>movie director</strong></strong></td>
 <td>$movie_director</td>
</tr>
<tr>

<tr>
 <td><strong>Lead Actor</strong></strong></td>
 <td>$movie_actor</td>
</tr>
<tr>

<tr>
 <td><strong>Running time</strong></strong></td>
 <td>$movie_runningtime</td>
</tr>
<tr>


<tr>
 <td><strong>Cost</strong></strong></td>
 <td>$movie_cost</td>
</tr>
<tr>


<tr>
 <td><strong>Takings</strong></strong></td>
 <td>$movie_takings</td>
</tr>
<tr>

<tr>
 <td><strong>Health</strong></strong></td>
 <td>$movie_health</td>
</tr>
<tr>


</table>
</div>

</body>
</html>
ENDHTML;



$table = <<<ENDHTML
<div style="text-align: center;">
<h2>The Ultimate movie database</h2>
<table border='1' cellpadding='1' cellspacing='2'
       style="width: 70%; margin-left: auto; margin-right: auto;">

<tr>
<th>Movie ID </th>
<th>Movie title</th>
<th>year of release </th>
<th>Movie director</th>
<th>Movie Actor</th>
<th>Movie type</th>
</tr>
ENDHTML;

?>

4 个答案:

答案 0 :(得分:2)

$movie_health = differences($row['movietakings'],$row['movie_cost']);

应该是

$movie_health = differences($row['movietakings'],$row['moviecost']);

注意最后一个变量。

答案 1 :(得分:0)

正如@ dev-null-dweller指出的那样,你可能实际上没有传递(242, 81)。编写单元测试,您会发现该函数在给定有效输入时可以正常工作。

<?php

function differences($takings,$cost)
{
  $difference = $takings - $cost;

  if($difference < 0) {
    $color = 'red';
    $difference = '$'.$difference.'million';
  } elseif($difference > 0) {
   $color = 'green';
   $difference = '$'.$difference.='million';
  } elseif($difference == 0) {
   $color = 'blue';
   $difference = "broken even ";
  }

  return '<span style="color:'.$color.';">'.$difference.'</span>';
}

class DifferencesTest extends PHPUnit_Framework_TestCase
{
  public function testValidInput() {
    $this->assertEquals('<span style="color:green;">$161million</span>', differences(242,81));
  }

  public function testInvalidInput() {
    $this->assertEquals('<span style="color:green;">$242million</span>', differences(242,NULL));
  }
}

答案 2 :(得分:0)

$movie_cost =$row['moviecost'].'million';
$movie_takings = $row['movietakings'].'million';
$movie_health = differences($row['movietakings'],$row['movie_cost']);

澄清我之前的回答:请注意'movie_cost'中是否存在下划线,而'moviecost'中缺少下划线。

答案 3 :(得分:-1)

我认为价值不会分配给成本变量。因此请检查函数中的成本变量。