当我登录网页然后解析html时，我有一个bash脚本。我使用的命令是wget：
wget --save-cookies=cookies.txt --post-data "uid=USER&pass=PWD" http://www.spanishtracker.com/login.php
wget --load-cookies=cookies.txt "http://www.spanishtracker.com/torrents.php" -O OUTPUT
现在，我正在尝试用Java制作这些。首先，我正在尝试POST请求，但是当我执行输出时，我没有记录。这些是Java的代码：
try {
data = URLEncoder.encode("uid", "UTF-8") + "=" + URLEncoder.encode("USER", "UTF-8");
data += "&" + URLEncoder.encode("pass", "UTF-8") + "=" + URLEncoder.encode("PASS", "UTF-8");
// Send the request
URL url = new URL("http://www.spanishtracker.com/index.php");
URLConnection conn = url.openConnection();
conn.setDoOutput(true);
OutputStreamWriter writer = new OutputStreamWriter(conn.getOutputStream());
//write parameters
writer.write(data);
writer.flush();
// Get the response
StringBuffer answer = new StringBuffer();
BufferedReader reader = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String line;
while ((line = reader.readLine()) != null) {
answer.append(line);
}
writer.close();
reader.close();
// temporary to build request cookie header
StringBuilder sb = new StringBuilder();
// find the cookies in the response header from the first request
List<String> cookies = conn.getHeaderFields().get("Set-Cookie");
if (cookies != null) {
System.out.println("Hay cookies para guardar");
for (String cookie : cookies) {
if (sb.length() > 0) {
sb.append("; ");
}
// only want the first part of the cookie header that has the value
String value = cookie.split(";")[0];
sb.append(value);
}
}