Question

我有这个SQL查询：

SELECT DISTINCT r.uri uri
FROM resource r
INNER JOIN object o ON o.idResource = r.idResource
WHERE r.type = 2
AND r.idResource IN (
  SELECT DISTINCT r1.idResource
  FROM object o1
  INNER JOIN resource r1 ON r1.idResource = o1.idResource
  INNER JOIN class c1 ON c1.idClass = o1.idClass
  INNER JOIN property p2 ON p2.idResource = c1.idResource
  INNER JOIN object_value ov2 ON ov2.idProperty = p2.idProperty
                             AND ov2.idObject = o1.idObject
  WHERE c1.idResource = 364
  AND (p2.idProperty = 4 AND ov2.value LIKE '%dave%')
)

在phpmyadmin（mysql）中正常工作，但在PHP代码中没有，它会给出超时。

$result = mysql_query('$gquery') or die(mysql_error());

知道为什么吗？

Answer 1

你不应该在引号中加$gquery。你应该使用

$result = mysql_query($gquery) or die(mysql_error());

Answer 2

已解决：超时问题。有必要延长超时期限。遗憾

查询在phpmyadmin中工作正常但在mysql_query php函数中没有

2 个答案: