Question

我需要创建一个查询，以便根据日期间隔返回N行。这很简单，但我不能：/

基本查询：

SELECT
  f.many_fields
FROM
  tb_foo f
WHERE
  f.id_foo = 14

此查询根据我的ID返回1行。但是，我在'2012-10-30'的日期间隔'2012-10-10'应用此查询，最后基本查询将根据日期间隔的差异返回20行。

可以做到吗？

SELECT
  f.many_fields,
  bar.*
FROM
  tb_foo f,
  (SELECT x FROM dual limit DATEDIFF('2012-10-10','2012-10-30')) bar
WHERE
  f.id_foo = 14

真实查询：

SELECT
  m.id_matricula,
  a.nome
FROM
  tb_matricula m
    inner join tb_aluno a on (a.id_aluno = m.id_matricula)
WHERE
  m.id_matricula = 14

开始日期= 2012-10-10 截止日期= 2012-10-30

我将在iReport上使用此结果，根据此日期之间的差异构建一个包含行数的网格。

基于Google搜索的示例：

SELECT
    CONCAT( dt.d ,'-' ,days.d ) AS dates
FROM
    (
        SELECT
            CONCAT( a1 ,b1 ) AS d
        FROM
            (
                SELECT
                    '0' AS a1
            UNION ALL SELECT
                    '1'
            UNION ALL SELECT
                    '2'
            UNION ALL SELECT
                    '3'
            ) a JOIN(
                SELECT
                    '0' AS b1
            UNION ALL SELECT
                    '1'
            UNION ALL SELECT
                    '2'
            UNION ALL SELECT
                    '3'
            UNION ALL SELECT
                    '4'
            UNION ALL SELECT
                    '5'
            UNION ALL SELECT
                    '6'
            UNION ALL SELECT
                    '7'
            UNION ALL SELECT
                    '8'
            UNION ALL SELECT
                    '9'
            ) b
        WHERE
            CONVERT(
                CONCAT( a1 ,b1 ) ,
                UNSIGNED
            ) <=(
                SELECT
                    DAY(
                        CONCAT( '2012-10' ,'-01' ) + INTERVAL 1 MONTH - INTERVAL 1 DAY
                    )
            )
            AND CONCAT( a1 ,b1 ) <> '00'
    ) days JOIN(
        SELECT
            '2012-10' AS d
    ) dt
 HAVING
    dates BETWEEN '2012-10-02' AND '2012-10-05'
ORDER BY
    dates
;

Answer 1

我找到了解决方法。使用子查询，我可以根据日期间隔返回许多行，与主查询没有任何关系。所以我有这个：

SELECT
    datas. * ,
    m.id_matricula ,
    p.nome
FROM
    tb_matricula m INNER JOIN tb_aluno a
        ON(
        a.id_aluno = m.id_aluno
    ) INNER JOIN tb_perfil p
        ON(
        p.id_perfil = a.id_perfil
    ) ,
    (
        SELECT
            CONCAT( dt.d ,'-' ,days.d ) AS dates
        FROM
            (
                SELECT
                    CONCAT( a1 ,b1 ) AS d
                FROM
                    (
                        SELECT
                            '0' AS a1
                    UNION ALL SELECT
                            '1'
                    UNION ALL SELECT
                            '2'
                    UNION ALL SELECT
                            '3'
                    ) a JOIN(
                        SELECT
                            '0' AS b1
                    UNION ALL SELECT
                            '1'
                    UNION ALL SELECT
                            '2'
                    UNION ALL SELECT
                            '3'
                    UNION ALL SELECT
                            '4'
                    UNION ALL SELECT
                            '5'
                    UNION ALL SELECT
                            '6'
                    UNION ALL SELECT
                            '7'
                    UNION ALL SELECT
                            '8'
                    UNION ALL SELECT
                            '9'
                    ) b
                WHERE
                    CONVERT(
                        CONCAT( a1 ,b1 ) ,
                        UNSIGNED
                    ) <=(
                        SELECT
                            DAY(
                                CONCAT( '2012-02' ,'-01' ) + INTERVAL 1 MONTH - INTERVAL 1 DAY
                            )
                    )
                    AND CONCAT( a1 ,b1 ) <> '00'
            ) days JOIN(
                SELECT
                    '2012-02' AS d
            ) dt
    UNION ALL SELECT
            CONCAT( dt.d ,'-' ,days.d ) AS dates
        FROM
            (
                SELECT
                    CONCAT( a1 ,b1 ) AS d
                FROM
                    (
                        SELECT
                            '0' AS a1
                    UNION ALL SELECT
                            '1'
                    UNION ALL SELECT
                            '2'
                    UNION ALL SELECT
                            '3'
                    ) a JOIN(
                        SELECT
                            '0' AS b1
                    UNION ALL SELECT
                            '1'
                    UNION ALL SELECT
                            '2'
                    UNION ALL SELECT
                            '3'
                    UNION ALL SELECT
                            '4'
                    UNION ALL SELECT
                            '5'
                    UNION ALL SELECT
                            '6'
                    UNION ALL SELECT
                            '7'
                    UNION ALL SELECT
                            '8'
                    UNION ALL SELECT
                            '9'
                    ) b
                WHERE
                    CONVERT(
                        CONCAT( a1 ,b1 ) ,
                        UNSIGNED
                    ) <=(
                        SELECT
                            DAY(
                                CONCAT( '2012-03' ,'-01' ) + INTERVAL 1 MONTH - INTERVAL 1 DAY
                            )
                    )
                    AND CONCAT( a1 ,b1 ) <> '00'
            ) days JOIN(
                SELECT
                    '2012-03' AS d
            ) dt
        ORDER BY
            dates
    ) datas
WHERE
    m.id_matricula = 42
    and
    datas.dates BETWEEN '2012-02-25' AND '2012-03-05';

为ID = 42和3天的日期差异运行此语句我有：

DATES,          ID_MATRICULA, NOME
2012-02-25  42        R ANDRE F DOMINGOS
2012-02-26  42        R ANDRE F DOMINGOS
2012-02-27  42        R ANDRE F DOMINGOS

MySQL根据日期间隔返回N行

1 个答案: