Question

我遇到自定义Wordpress MySQL查询的问题。我的情况是这样的：我有关于帖子的常规帖子类型'post'和自定义帖子类型''authors'，有关作者的信息。 “作者”的帖子类型包含所有作者，但并非所有作者都需要作为帖子的作者。

每个帖子（类型'post'和'author'）都有一个带有作者确切名称的自定义分类（例如“John Smith”）。帖子类型“作者”为作者的名字和姓氏提供了额外的自定义元值（因为它们可能变得复杂，并且更容易按姓氏，名字排序）。

现在我正在尝试选择发布帖子的所有作者，计算他们的帖子数量并显示与他们的名字相关的元值。我不确定如何从一个帖子类型（'post'）交叉引用分类法，而meta值在另一行中形成另一个（'author'）。

我想要的是什么：

John Smith    John    Smith    10

到目前为止我得到了什么：

John Smith    10    John
John Smith    10    Smith

我坚持下面的查询。任何帮助将不胜感激！

SELECT
    N, C, meta_value
    FROM
        (SELECT
            t.name AS N, count(*) AS C
                FROM
                    wp_2_posts p
                    INNER JOIN wp_2_term_relationships AS tr ON p.ID=tr.object_id
                    INNER JOIN wp_2_term_taxonomy AS tt ON tr.term_taxonomy_id = tt.term_taxonomy_id
                    INNER JOIN wp_2_terms AS t ON tt.term_id = t.term_id
                WHERE 1=1
                    AND tt.taxonomy = 'myauthor'
                    AND p.post_type = 'post'
                    AND p.post_status = 'publish'
                GROUP BY
                    N
                ORDER BY
                C DESC) AS x
        INNER JOIN wp_2_posts p2
        INNER JOIN wp_2_term_relationships AS tr2 ON p2.ID=tr2.object_id
        INNER JOIN wp_2_term_taxonomy AS tt2 ON tr2.term_taxonomy_id = tt2.term_taxonomy_id
        INNER JOIN wp_2_terms AS t2 ON tt2.term_id = t2.term_id
        INNER JOIN wp_2_postmeta AS m2 ON m2.post_id = p2.ID
            WHERE 1=1
                AND post_type = 'author'
                AND t2.name = x.N
                AND (m2.meta_key = 'lastname' OR m2.meta_key = 'firstname')

Answer 1

这是一个相当不合理的解决方案，关于如何改进它的任何想法？

SELECT
    N, C, m2.meta_value AS L, m3.meta_value AS F
    FROM
        (SELECT
            t.name AS N, count(*) AS C
                FROM
                    wp_2_posts p
                    INNER JOIN wp_2_term_relationships AS tr ON p.ID=tr.object_id
                    INNER JOIN wp_2_term_taxonomy AS tt ON tr.term_taxonomy_id = tt.term_taxonomy_id
                    INNER JOIN wp_2_terms AS t ON tt.term_id = t.term_id
                WHERE 1=1
                    AND tt.taxonomy = 'myauthor'
                    AND p.post_type = 'post'
                    AND p.post_status = 'publish'
                GROUP BY
                    N) AS x
        INNER JOIN wp_2_posts p2
        INNER JOIN wp_2_term_relationships AS tr2 ON p2.ID=tr2.object_id
        INNER JOIN wp_2_term_taxonomy AS tt2 ON tr2.term_taxonomy_id = tt2.term_taxonomy_id
        INNER JOIN wp_2_terms AS t2 ON tt2.term_id = t2.term_id
        INNER JOIN wp_2_postmeta AS m2 ON m2.post_id = p2.ID
        INNER JOIN wp_2_posts p3
        INNER JOIN wp_2_term_relationships AS tr3 ON p3.ID=tr3.object_id
        INNER JOIN wp_2_term_taxonomy AS tt3 ON tr3.term_taxonomy_id = tt3.term_taxonomy_id
        INNER JOIN wp_2_terms AS t3 ON tt3.term_id = t3.term_id
        INNER JOIN wp_2_postmeta AS m3 ON m3.post_id = p3.ID
            WHERE 1=1
                AND p3.post_type = 'author'
                AND t3.name = x.N
                AND m3.meta_key = 'firstname'
                AND p2.post_type = 'author'
                AND t2.name = x.N
                AND m2.meta_key = 'lastname'
    ORDER BY
        C DESC,
        L

Wordpress自定义查询：从一个帖子类型交叉引用自定义分类，使用另一个自定义元素

1 个答案: