在上传文件PHP代码时自动重命名相同的文件名

Question

multiple_upload.php

下面的代码是multiple_upload.php，它有2个上传按钮和一个提交按钮。 实际情况：

<table width="500" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<form action="multiple_upload_ac.php" method="post" enctype="multipart/form-data" name="form1" id="form1">
<td>
<table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF">
<tr>
<td><strong>multiple Files Upload </strong></td>
</tr>
<tr>
<td>Select file 
<input name="ufile[]" type="file" id="ufile[]" size="50" /></td>
</tr>
<tr>
<td>Select file
<input name="ufile[]" type="file" id="ufile[]" size="50" /></td>
</tr>
<tr>
<td align="center"><input type="submit" name="Submit" value="Upload" /></td>
</tr>
</table>
</td>
</form>
</tr>
</table>

multiple_upload_ac.php

此代码将处理您放入此代码行<input name="ufile[]" type="file" id="ufile[]" size="50" />的文件，它将保存在我的上传文件夹中。

<?php

//set where you want to store files
//in this example we keep file in folder upload 
//$HTTP_POST_FILES['ufile']['name']; = upload file name
//for example upload file name cartoon.gif . $path will be upload/cartoon.gif

$path1= "upload/".$HTTP_POST_FILES['ufile']['name'][0];
$path2= "upload/".$HTTP_POST_FILES['ufile']['name'][1];


//copy file to where you want to store file
copy($HTTP_POST_FILES['ufile']['tmp_name'][0], $path1);
copy($HTTP_POST_FILES['ufile']['tmp_name'][1], $path2);

// Use this code to display the error or success.

$filesize1=$HTTP_POST_FILES['ufile']['size'][0];
$filesize2=$HTTP_POST_FILES['ufile']['size'][1];


if($filesize1 || $filesize2!= 0) 
{
echo "We have recieved your files";
}
else {
echo "ERROR.....";
}

// What files that have a problem? (if found)

if($filesize1==0) {
echo "There're something error in your first file";
echo "<BR />";
}

if($filesize2==0) {
echo "There're something error in your second file";
echo "<BR />";
}
?>

这是我的问题： 例如，如果可能的话，我上传samplefile.ppt而另一个用户上传相同的文件名和文件类型（samplefile.ppt）..如果可行的话，新上传的文件名就像samplefile（1）.ppt或samplefile_1.ppt因为有一个现有的文件，当其他用户再次上传时，该文件将变为samplefile（2）.ppt或samplefile_2.ppt。 谢谢

Answer 1

在复制文件之前，使用file_exists检查文件是否已存在。

如果存在，请将文件名更改为您想要的内容，我还建议您循环执行所有这些操作，不要重复。

如下：

if( file_exists($path1) ) {
    // change another filename to overwrite $path1
}

很抱歉，我忘了检查文件是否存在，即使它有计数，所以除了简单的if之外，你还有一些更复杂的工作要做，以下是编辑后的代码：

for( $i = 0; isset($HTTP_POST_FILES['ufile']['name'][$i]); $i++ ) {
    /*
     * do things before copy
     */
    $path = 'upload/'.$HTTP_POST_FILES['ufile']['name'][$i];
    $lastDot = strrpos($path, '.');
    $base = substr($file, 0, $lastDot);
    $ext = substr($file, $lastDot);
    // this loop will keep doing until find a path that no file exists
    for( $seq = 0; file_exists($path); $seq++ ) {
        if( file_exists($path) ) {
            $path = $base . '_'. $seq. $ext;
        }
    }
    /*
     *  do copy and something else
     */
}

Answer 2

您可以在复制之前使用file_exists()进行检查，并使用pathinfo()查看文件信息，例如：

$file = $HTTP_POST_FILES['ufile']['tmp_name'][0];
$path_info = pathinfo($file);
$count = 0;

while(file_exists($file) {
    $count ++;
    $file = $path_info['dirname'] . $path_info['filename'] '_' . $count . '.' $path_info['extension'];
}

copy($file, $path) ;