我有一个使用GridViewColumnCollection的MultiColumn TreeView。我的情况,我不知道会有多少列,也不知道它们的标题名称。这是在运行时发现的。
因此,我需要在代码中创建这些列并动态绑定它们。
好的 - 创作很简单:
GridViewColumn c = new GridViewColumn();
c.Header = "Next Column";
myTree.Columns.Add(c);
现在我绊倒了 - 假设我希望绑定到我的viewModel的“MyName”属性:
Binding myBinding = new Binding(??);
myBinding.Source = ??
BindingOperations.SetBinding(myTree,GridViewColumn.???? , myBinding);
现在是这个
的模板 <DataTemplate x:Key="CellTemplate_Name">
<DockPanel>
<ToggleButton x:Name="Expander"
Margin="{Binding Level,
Converter={StaticResource LevelToIndentConverter},
RelativeSource={RelativeSource AncestorType={x:Type l:TreeListViewItem}}}"
ClickMode="Press"
IsChecked="{Binding Path=IsExpanded,
RelativeSource={RelativeSource AncestorType={x:Type l:TreeListViewItem}}}"
Style="{StaticResource ExpandCollapseToggleStyle}" />
<TextBlock Text="{Binding Name}" />
.
.
.
<Style TargetType="{x:Type l:TreeListViewItem}">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type l:TreeListViewItem}">
<StackPanel>
<Border Name="Bd"
Background="{TemplateBinding Background}"
BorderBrush="{TemplateBinding BorderBrush}"
BorderThickness="{TemplateBinding BorderThickness}"
Padding="{TemplateBinding Padding}">
<GridViewRowPresenter x:Name="PART_Header"
Columns="{Binding Path=Columns,
RelativeSource={RelativeSource AncestorType={x:Type l:TreeListView}}}"
Content="{TemplateBinding Header}" />
</Border>
<ItemsPresenter x:Name="ItemsHost" />
</StackPanel>
XAML中的列插入和绑定显示为:
<l:TreeListView x:Name="myTree" ItemsSource="{Binding MySource}">
<l:TreeListView.Columns>
<GridViewColumn x:Name="GridViewColumn0" CellTemplate="{StaticResource CellTemplate_Name}"
Header="Name" />
<GridViewColumn Width="60"
DisplayMemberBinding="{Binding Description}"
Header="Description" />
任何有关SetBinding的帮助都将非常感谢。我一直在搜寻,直到我的手指脱落。
更新: 优秀的答案:
GridViewColumn c = new GridViewColumn();
c.Header = "Next Column";
myTree.Columns.Add(c);
Binding myBinding = new Binding("MyName");
myBinding.Source = viewModel;
BindingOperations.SetBinding(myTree.Columns[myTree.Columns.Count - 1],
GridViewColumn.HeaderProperty,
myBinding);
绑定现在可以完美地对抗Header - 非常感谢你。
答案 0 :(得分:2)
(从评论中提取答案:)
您可以使用以下代码手动设置绑定:
Binding myBinding = new Binding("MyName");
myBinding.Source = viewModel;
BindingOperations.SetBinding(myTree.Columns[i], GridViewColumn.HeaderProperty, myBinding);
其中i
是列数。
要设置DisplayMemberBinding
,可以使用更简单的代码:
Binding descriptionBinding = new Binding("Description");
myTree.Columns[i].DisplayMemberBinding = descriptionBinding;
答案 1 :(得分:0)
我将它设为方法NewGridViewColumn
,将参数header
和bindingName
设置为方法,您将获得一个绑定完成的GridViewColumn:
private GridViewColumn NewGridViewColumn(string header, string bindingName)
{
GridViewColumn gvc = new GridViewColumn();
gvc.Header = header;
gvc.DisplayMemberBinding = new Binding(bindingName);
return gvc;
}
然后在ListView xaml的情况下:
<Grid>
<ListView Margin="5" Name="ListViewTest"></ListView>
</Grid>
您可以使用NewGridViewColumn
在构造函数中轻松地将GridViewColumn添加到ListView:
public MainWindow()
{
InitializeComponent();
//Give the Source to ListViewTest
//ProduceNames() makes a List<NameClass> that
//NameClass has 3 property Name1,Name2,Nmae3
ListViewTest.ItemsSource = ProduceNames();
GridView gview = new GridView();
//add some GridViewColumns to the gview
gview.Columns.Add(NewGridViewColumn("FirstName","Name1"));
gview.Columns.Add(NewGridViewColumn("SecondName","Name2"));
gview.Columns.Add(NewGridViewColumn("ThirdName","Name3"));
//set the gview to the ListViewTest's View
ListViewTest.View = gview;
}
结果: