Question

我即将爆炸。我一直在寻找两个小时来解决这个问题。我在setTimer方法中有一个switch语句。当我调试程序时，timerType值在方法运行时发生变化，但是一旦退出，timerType将恢复为null。这使我的case语句变得毫无用处，因为我需要在下次调用方法时进行更改。我很乐意帮助你，因为我确信它像往常一样简单:(。我尝试将它更改为int以查看它是否与String类型或其他任何事情有关。我有点像菜鸟。请停止我不再挣扎（至少在这个特殊的问题:) :)

public string timerType;



if (checkRoundChanged()) {
     SoundPlayer.Play();
     setTimer(timerType);
}

和方法

protected void setTimer(String timerType){
        switch (timerType) {
            case "ready":
                secLeft = readySec;
                minLeft = readyMin;
                timerType = "round";
                break;
            case "round":
                secLeft = roundSec;
                minLeft = roundMin;
                timerType = "rest";
                break;
            case "rest":
                secLeft = restSec;
                minLeft = restMin;
                timerType = "round";
                break;
            case "relax":
                secLeft = relaxSec;
                minLeft = relaxMin;
                timerType = "done";
                break;
            default:
                timerType = "ready";
                break;
        }

    }

三江源！

Answer 1

字符串按值传递，而不是通过引用传递。您可以返回新值：

protected string setTimer(String timerType){
    switch (timerType) {
        case "ready":
            secLeft = readySec;
            minLeft = readyMin;
            timerType = "round";
            break;
        case "round":
            secLeft = roundSec;
            minLeft = roundMin;
            timerType = "rest";
            break;
        case "rest":
            secLeft = restSec;
            minLeft = restMin;
            timerType = "round";
            break;
        case "relax":
            secLeft = relaxSec;
            minLeft = relaxMin;
            timerType = "done";
            break;
        default:
            timerType = "ready";
            break;
    }

    return timerType;
}

....

timerType =  setTimer(timerType);

或通过引用传递：

protected void setTimer(ref String timerType) {
   ...
   timerType = newValue;
   ...
}

setTimer(ref timerType);

以下是一些recommended reading。

方法完成后，我的变量会继续切换回来

1 个答案: