如何保护php图片上传系统

时间:2012-10-27 07:52:42

标签: php security upload system image

我想用php制作图片上传系统,我希望用户只需上传即可 png,jpg文件,而不是病毒或其他文件。我怎么能这样做?

3 个答案:

答案 0 :(得分:1)

步骤1:检查扩展名(扩展名文件以...结尾)

第2步:检查MIME类型($ file_info = getimagesize($ _ FILES ['image_file']; $ file_mime = $ file_info ['mime'];)

仅允许您要上传的图片扩展名,因为您可以制作白名单

尝试类似

的内容
$whitelist = array(".jpeg",".jpg",".png");
foreach ($whitelist as $item)
    {


       if(preg_match("/$item\$/i", $_FILES['uploadfile']['name']))
               {
                   $uploaddir='uploads/uploads_image/';
                   $uploadfilename=mysql_prep(basename($_FILES['uploadfile']['name']));
                    $iv_size = mcrypt_get_iv_size(MCRYPT_RIJNDAEL_256, MCRYPT_MODE_ECB);
                   $iv=  mcrypt_create_iv($iv_size,MCRYPT_DEV_RANDOM);
                   $newname= mcrypt_encrypt(MCRYPT_RIJNDAEL_256, "this is the key",$uploadfilename.time(), MCRYPT_MODE_ECB, $iv);
                   $newfilename=  (bin2hex($newname));
                   $uploadfile=$uploaddir.$newfilename.".png";
                   $access=true;
               }
    }

如果用户尝试通过制作黑名单来上传杂项文件,您也可以阻止用户的IP

foreach ($blacklist as $item) 
    {
        if(preg_match("/$item\$/i", $_FILES['uploadfile']['name'])) 
            {
                $network = ip2long("10.12.0.0");
                $mask = ip2long("255.255.0.0");
                $ip = ip2long($_SERVER{'REMOTE_HOST'});
                if (($network & $mask) == ($ip & $mask)) {
                  die("Unauthorized");
                }
            }


    }

答案 1 :(得分:1)

 ($_FILES["file"]["type"] == "image/png")

有关此click here

的详细信息

答案 2 :(得分:0)

1st check:-
//check if contain php and kill it 
 $pos = strpos($filename,'php');
 if(!($pos === false)) {
  die('error');
 }

2nd check:-
//get the file ext
 $file_ext = strrchr($filename, '.');
$image_list = array(".jpg",".jpeg",".gif",".png"); 
 if (!(in_array($file_ext, $image_list))) {
        die('not allowed extension,please upload images only');
 }


3rd check:-    
$fileType = $_FILES["uploaded_file"]["type==image/jpeg || image/gif || image/png"];

4th check:-     
preg_match("/.(gif|jpg|png)$/i", $fileName);

hope these checks solve your problem....