我的XML如下所示
<?xml version="1.0" encoding="UTF-8"?>
<Set>
<Bundles>
<BundleID>1</BundleID>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>34675</TrackingID>
</BundleDetails>
<BundleQty>12</BundleQty>
</Bundles>
<Bundles>
<BundleID>2</BundleID>
<BundleDetails>
<Classification>B</Classification>
<TrackingID>4563</TrackingID>
</BundleDetails>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>4563</TrackingID>
</BundleDetails>
<BundleQty>34</BundleQty>
</Bundles>
<Bundles>
<BundleID>3</BundleID>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>2343243</TrackingID>
</BundleDetails>
<BundleQty>22</BundleQty>
</Bundles>
<Bundles>
<BundleID>4</BundleID>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>123231</TrackingID>
</BundleDetails>
<BundleDetails>
<Classification>B</Classification>
</BundleDetails>
<BundleDetails>
<Classification>B</Classification>
<TrackingID>42342</TrackingID>
</BundleDetails>
<BundleQty>33</BundleQty>
</Bundles>
<Bundles>
<BundleID>5</BundleID>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>123231</TrackingID>
</BundleDetails>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>42342</TrackingID>
</BundleDetails>
<BundleDetails>
<Classification>B</Classification>
<TrackingID>124512</TrackingID>
</BundleDetails>
<BundleQty>21</BundleQty>
</Bundles>
</Set>
我需要获取每个Set / Bundles的详细信息,如下所示
Bundle# Qty Classes
1 12 A
2 34 A,B
3 22 A
4 33 A,B
5 21 A,B
我从下面开始,但是获得了不同的类列表。需要一些指导,
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<p>Set Details</p>
<table>
<xsl:for-each select="Set/Bundles">
<tr>
<td><xsl:value-of select="BundleID"/></td>
<td><xsl:value-of select="BundleQty"/></td>
<td>--Distinct List of ./BundleDetails/Classification </td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
提前感谢您的帮助!
谢谢!
答案 0 :(得分:2)
此转化:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="kClassByValAndGrParent" match="Classification"
use="concat(generate-id(../..),'+', .)"/>
<xsl:template match="*"><xsl:apply-templates/></xsl:template>
<xsl:template match="/*">
<table border="1">
<tr>
<th>Bundle#</th><th>Qty</th><th>Classes</th>
</tr>
<xsl:apply-templates/>
</table>
</xsl:template>
<xsl:template match="Bundles">
<tr>
<xsl:apply-templates select="*[not(self::BundleDetails)]"/>
<td>
<xsl:apply-templates select=
"BundleDetails/Classification
[generate-id()
=
generate-id(key('kClassByValAndGrParent',
concat(generate-id(../..),'+', .)
)[1]
)
]
"/>
</td>
</tr>
</xsl:template>
<xsl:template match="BundleID|BundleQty">
<td><xsl:value-of select="."/></td>
</xsl:template>
<xsl:template match="BundleDetails"/>
<xsl:template match="Classification">
<xsl:if test="position() > 1">,</xsl:if>
<xsl:value-of select="."/>
</xsl:template>
<xsl:template match="text()"/>
</xsl:stylesheet>
应用于提供的XML文档:
<Set>
<Bundles>
<BundleID>1</BundleID>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>34675</TrackingID>
</BundleDetails>
<BundleQty>12</BundleQty>
</Bundles>
<Bundles>
<BundleID>2</BundleID>
<BundleDetails>
<Classification>B</Classification>
<TrackingID>4563</TrackingID>
</BundleDetails>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>4563</TrackingID>
</BundleDetails>
<BundleQty>34</BundleQty>
</Bundles>
<Bundles>
<BundleID>3</BundleID>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>2343243</TrackingID>
</BundleDetails>
<BundleQty>22</BundleQty>
</Bundles>
<Bundles>
<BundleID>4</BundleID>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>123231</TrackingID>
</BundleDetails>
<BundleDetails>
<Classification>B</Classification>
</BundleDetails>
<BundleDetails>
<Classification>B</Classification>
<TrackingID>42342</TrackingID>
</BundleDetails>
<BundleQty>33</BundleQty>
</Bundles>
<Bundles>
<BundleID>5</BundleID>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>123231</TrackingID>
</BundleDetails>
<BundleDetails>
<Classification>A</Classification>
<TrackingID>42342</TrackingID>
</BundleDetails>
<BundleDetails>
<Classification>B</Classification>
<TrackingID>124512</TrackingID>
</BundleDetails>
<BundleQty>21</BundleQty>
</Bundles>
</Set>
生成想要的正确结果:
<table border="1">
<tr>
<th>Bundle#</th>
<th>Qty</th>
<th>Classes</th>
</tr>
<tr>
<td>1</td>
<td>12</td>
<td>A</td>
</tr>
<tr>
<td>2</td>
<td>34</td>
<td>B,A</td>
</tr>
<tr>
<td>3</td>
<td>22</td>
<td>A</td>
</tr>
<tr>
<td>4</td>
<td>33</td>
<td>A,B</td>
</tr>
<tr>
<td>5</td>
<td>21</td>
<td>A,B</td>
</tr>
</table>
<强>解释强>:
正确使用 Muenchian Grouping Method 。
正确的复合 key 定义,指定任何Classification
作为其祖父项及其字符串值的函数。