查询以显示具有2列重复值的行

Question

我有Table1：

id|name|city
-------------
1 | bat|nyc
2 | cat|del
2 | rat|bom
3 | mat|xyz

表2

id|name|city
--------------
1 |bat|dsada
2 |cat|sadasd
3 |rat|sdasdas
2 |rat|asdas

我需要一个查询来显示两个表中的BOTH id和name相同的行，上面的例子中查询必须返回 我需要一个查询来显示行

1|bat|nyc
2|cat|del 

来自第一张表

Answer 1

最简单（也可能是最有效）的方法是使用EXISTS：

SELECT id,name,city FROM Table1 t1
WHERE EXISTS
(
   SELECT 1 FROM Table2 t2
   WHERE t2.name = t1.name
   AND t2.id  = t1.id
)

Answer 2

尝试加入表格，如下所示

select tabl1.* from table1
inner join table2
on table1.id=table2.id and table1.name=table2.name

Answer 3

select
   T1.id, T1.name
from Table1 as T1
where
    exists (select * from Table2 as T2 where T2.id = T1.id and T2.name = T1.name)

Answer 4

试试这个：JOIN将确保满足两个条件，即两个表中的两个记录都具有id和name的相同值

Select t1.name, t1.city from Table1 t1
 Join Table2 t2
  ON t1.id = t2.id and 
        t1.name = t2.name