Question

上周我开始使用expresso paser（www.sxml.com.au），因为它在本网站上被视为解决方案。我创建了一个免费帐户，登录，上传了一个XML文件并解析了该文件。我可以在屏幕上看到结果很好。然后我在java中生成客户端代码并运行它。

我使用HTTP运行非SSL版本，我从SXML服务器收到此错误。

还有其他人有此经验吗？

请尽快帮助，因为我需要尽快将其整合到项目中!!

这是我的客户端代码中连接到SXML服务器并发出请求的部分。

String username = "adamCoyle";
String password = ""; //ADD PASSWORD HERE
String connectionName = "test1";
String company = "student";
String remoteSXMLURL="http://sxml.com.au:8080/Expresso/RemoteSXML";
/*
 * Non- SSL mode
 */
/*
* For SSL mode, uncomment the following code and follow certificate installation     instructions in help section
* of website to install the SSL cert into the CA keystore
*/
//String remoteSXMLURL="https://sxml.com.au:8444/Expresso/RemoteSXML";

String urlParams ="";

String fileLocation = "server";

String fileForXMLUpload = "";

if(fileForXMLUpload!="")

{

File xmlFileToBeUploadedFile = new File (fileForXMLUpload);

fileForXMLUpload="";

if(xmlFileToBeUploadedFile.exists())

{

BufferedReader bfr = new BufferedReader(new FileReader (xmlFileToBeUploadedFile));

while(bfr.ready())

{

fileForXMLUpload+=bfr.readLine();

}

}

}

String mode= "all";

String isCached = "false";

String areRulesSimple ="false";

String dynamicParamaters ="";

String sortBy ="";

/* step 2 - make a https connection */

URL sxml = new URL(remoteSXMLURL);

HttpURLConnection yc = (HttpURLConnection) sxml.openConnection();

/* step 3- add the paramaters to the HTTPS connection */

String urlParameters = "username="

+ URLEncoder.encode(username, "UTF-8") + "&password="

+ URLEncoder.encode(password, "UTF-8") + "&connectionName="

+ URLEncoder.encode(connectionName, "UTF-8") + "&company="

+ URLEncoder.encode(company, "UTF-8") + "&fileLocation="

+ URLEncoder.encode(fileLocation, "UTF-8") + "&fileForXMLUpload="

+ URLEncoder.encode(fileForXMLUpload, "UTF-8") + "&mode="

+ URLEncoder.encode(mode, "UTF-8") + "&isCached="

+ URLEncoder.encode(isCached, "UTF-8") + "&areRulesSimple="

+ URLEncoder.encode(areRulesSimple, "UTF-8") + "&dynamicParamaters="

+ URLEncoder.encode(dynamicParamaters, "UTF-8") + "& urlParams ="

+ URLEncoder.encode(urlParams, "UTF-8") + "&sortBy="

+ URLEncoder.encode(sortBy, "UTF-8");

/* step 4- set the properties for the HTTPS connection */

/*

* properties

* requestMethod - The HTTPS request will always be a POST request

* Content-Type - The content type is application/x-www-form-urlencoded

* content-Length - This is the length of the paramaters

*

*/

yc.setRequestMethod("POST");

yc.setRequestProperty("Content-Type","application/x-www-form-urlencoded");

yc.setRequestProperty("Content-Length","" + Integer.toString(urlParameters.getBytes().length));

yc.setRequestProperty("Content-Language", "en-US");

yc.setDoOutput(true);

/* step 5 - push out request to HTTPS server */

DataOutputStream wr = new DataOutputStream(yc.getOutputStream());

wr.writeBytes(urlParameters);

wr.flush();

wr.close();

Answer 1

首先，感谢您使用SXML。我们真的在努力让尽可能多的开发人员使用它。

我查看了您的客户端代码并且缺少一个字段。要使用Expresso XML解析器，您需要提供密码。这与您用于登录GUI帐户的密码相同。出于安全原因，您的密码不会自动添加到客户端代码中，但您需要连接它。

找到代码

的部分

String password =“”; //在这里添加密码

添加密码代替空白字符串，然后再次尝试连接。你应该能够连接。

请告诉我您是否还有其他问题。

劳拉卡瓦纳 www.sxml.com.au

与Expresso一起使用客户端代码时出错

1 个答案: